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4 years ago

What is the solution for x in the equation? -2x + 14 + 10x = 34

Mathematics

2 answers:

Kryger [21]4 years ago

7 0

Answer:

Decimal: x = 2.5

Fraction: x=5/2

Marina CMI [18]4 years ago

4 0

Answer: The answer for this is x=5/2

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Need Help PLLLEEAASSSSEEEE,

Licemer1 [7]

(x-1)^2= 16(y-2)

(^2 is the exponent)

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3 years ago

Terence is working on this problem: 53.04 x 4.6 = ? Terence solves the problem and finds 53.04 x 4.6 =

Scorpion4ik [409]

Answer:

Too few decimal points.

Step-by-step explanation:

53.04 x 4.6 = 243.984.

6 0

2 years ago

M is between points C and Q. CM=17 and CQ=21. What is MQ?

katrin2010 [14]

Sometimes it helps to draw it out...

(17)
C_______M_________Q
|___________________|
21

therefore, CM + MQ = CQ
17 + MQ = 21
MQ = 21 - 17
MQ = 4 <===

8 0

3 years ago

Read 2 more answers

Based on probability and if it is appropriate for a decision to be left up to chance, choose every situation that is both statis

svet-max [94.6K]

The situations that are both statistically fair and morally fair are Situation 2, Situation 3 and Situation 5

<h3>How to categorize the situations?</h3>

For a situation to be fair, the probability of every outcome must be equal.

We can now analyze each option using the above highlight

Situation 1

Alphabets = 26
Probability of vowel = 5/26
Probability of consonant = 21/26

The probabilities of vowels and consonant are not equal.

Hence, this situation is not fair

Situation 2

People = 4

P(Each) = 1/4

The probability of each participant is equal in the above scenario i.e. 1/4

Hence, this situation is fair

Situation 3

People = 5
P(Each) = 1/5

The probability of each cousin is equal in the above scenario i.e. 1/5

Hence, this situation is fair

Situation 4

Numbers = 5 i.e. 2 to 6
P(Prime) = 3/5
P(Composite) = 4/6

The probabilities of prime and composite numbers are not equal.

Hence, this situation is not fair

Situation 5

Roommates = 5
Cards = 5
Aces = 4
P(Each) = 1/5

All probabilities are equal in the above scenario i.e. 1/5

Hence, this situation is fair

Read more about probability at:

brainly.com/question/251701

#SPJ1

4 0

3 years ago

Area of the Region Between Curves-Please help.

Neporo4naja [7]

Answer: 32/3

Step-by-step explanation:

To find the area of the region between the curves, you first want to find the interval of both curves. You can do that by setting both curves equal to each other.

$-\frac{1}{2}x^2+2=\frac{1}{2} x^2-2$ [subtract both sides by 2]

$-\frac{1}{2}x^2= \frac{1}{2} x^2-4$ [subtract both sides by $\frac{1}{2} x^2$ ]

$-x^2=-4\\x=2,-2$

Now that we know the interval, we set this into an integral and subtract the top curve by the bottom curve. *Note: I can't type in -2 into the interval, therefore only a "-" will be displayed.

$\int\limits^2_- {|-\frac{1}{2}x^2+2-(\frac{1}{2}x^2-2) | } \, dx$ [distribute -1]

$\int\limits^2_-{|-\frac{1}{2}x^2+2-\frac{1}{2}x^2+2 |} \, dx$ [combine like terms]

$\int\limits^2_- {|-x^2+4|} \, dx$ [solve integral]

$\frac{32}{3}$

The area between the curves is 32/3. This was also the reason why we had the absolute values because area can never be negative.

6 0

4 years ago