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Licemer1 [7]
3 years ago
13

Can someone please help pleaseeee!!!

Mathematics
1 answer:
olasank [31]3 years ago
5 0
The sum is y(4y − 1) + <span>(y + 5)2 = 4y² -y +y² +25 - 10y = 5y²-11y + 25 
the answer is </span><span>5y2 − 11y + 25

</span>
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Look at the graph shown:
lidiya [134]

Answer:

y = 3x - 1

Step-by-step explanation:

Although the coordinate plane is not given, we don't need it to find the solution. We have given all the conditions enough for the solution.

The y-intercept is (-1) and the function passes through the point ( 1, 2 ).

Only the function y = 3x -1 matches these conditions.

We can observe the points in the attached graph.

5 0
3 years ago
Read 2 more answers
Which relationship is always true for the angles x, y, and z of triangle MNP?
Reil [10]
In every triangle, all the measures of the angles combined is 180 degrees.

So x + y + z = 180 degrees
4 0
3 years ago
Laqueta has three times as many quarters as Pablo if they each spend $.50 Laqueta will have five times as many quarters as Pablo
masya89 [10]

Answer:

Number of quarters with Pablo = 4

Number of quarters with Laqueta = 12

Step-by-step explanation:

Given that:

Laqueta has three times as many quarters as Pablo.

They both spend $0.50.

After that Laqueta will have 5 times as many quarters as Pablo.

To find:

Number of quarters with Laqueta and Pablo now?

Solution:

Let number of quarters with Laqueta = x

Let number of quarters with Pablo = y

As per given statement:

x=3y ..... (1)

In $0.50, there are 2 quarters:

After spending $0.50, number of quarters left with both of them:

Number of quarters left with Laqueta = x - 2 =  3y-2

Money left with Pablo = y - 2

As per given statement:

3y-2 = 5(y-2)\\\Rightarrow 3y-2 = 5y-10\\\Rightarrow 2y = 8\\\Rightarrow y = 4

Therefore, the answer is:

Number of quarters with Pablo = 4

Number of quarters with Laqueta = 3 \times 4 = 12

8 0
3 years ago
8 points
Zigmanuir [339]

Answer:

10/40 = 25%

Step-by-step explanation:

40 total = denominator

30 cheese - 40 total = 10 not cheese

10/40

8 0
3 years ago
2x2 − 10x − 28 6x × 6 x − 7
Simora [160]

Answer:

no real solutions

Step-by-step explanation:

If equation is...

2x^2 - 10x - 28 = 6x(6x) - 7\\2x^2 - 10x - 28 = 6x^2 - 7\\0 = 4x^2 + 10x + 21\\4x^2 + 10x + 21 = 0

= no real solutions

7 0
3 years ago
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