Answer:
The minimum value of the width is 15 ft and the maximum value of the width is 30 ft
Step-by-step explanation:
Let
x -----> the length of the deck
y ----> the width of the deck
we know that
The perimeter of the deck is equal to


so


-----> equation A
The area is equal to
-----> inequality B

Solve the quadratic equation by graphing
The possible width of the deck are the values of y in the interval
[15,30]
All real numbers greater than or equal to 15 ft and less than or equal to 30 ft
see the attached figure
The minimum value of the width is 15 ft and the maximum value of the width is 30 ft
D because of since and the world
Hello!
First of all let's look at points L and L'. The coordinates for L are (-5,-4) and the coordinates for L' are at (0,3).
First of all let's think about the vertical translation. This is the change in the y-axis. As you can see, the difference of 3 and -4 is 7. This means there was a vertical translation of 7, or it was moved up 7 units.
Now we have the horizontal translation, or the change in the x-axis. The difference of -5 and 0 is 5. Therefore it had a horizontal translation of 5.
(-5,-4)⇒(0,3) was translate up 7 units and translated right 5 units.
I hope this helps!