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Fudgin [204]
2 years ago
6

The length of a rectangle is twice it’s width. If the area of the rectangle is 72ft ^2, find it’s perimeter

Mathematics
1 answer:
alisha [4.7K]2 years ago
7 0

Hi!

length = l = 2 * width = 2 * w

Area = l * w = l * 2 * l = 2 * l^2

2 * l^2 = 72

l^2 = 72/2 = 36

l = square root of 36

l = 6

l = 2 * w => w = l/2 = 6/2 = 3

Perimeter = 2 * l + 2 * w = 2 * 6 + 2 * 3 = 12 + 6 = 18 feet

Hope this helps!

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See the explanation for the answer.

Step-by-step explanation:

Given function:

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p_{3}(x) = 81^{1/4} + \frac{1}{4(81)^{ 3/4} }  (x-81)+ (\frac{1}{2})(-\frac{3}{16(81)^{7/4} } ) (x-81)^{2} +  (\frac{1}{6})(\frac{21}{64(81)^{11/4} } ) (x-81)^{3}

p_{3} (x) = 3 + 0.0092592593 (x - 81) + 1/2 ( - 0.000085733882) (x - 81)² + 1/6  

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p_{3} (x)  =  0.0092592593 x - 0.000042866941 (x - 81)² + 0.00000030871254

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Hence approximation at given quantity i.e.

x = 94

Putting x = 94

p_{3} (94)  =  0.0092592593 (94) - 0.000042866941 (94 - 81)² +          

                                                                 0.00000030871254 (94-81)³ + 2.25

         = 0.87037 03742 - 0.000042866941 (13)² + 0.00000030871254(13)³ +    

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         = 0.87037 03742 - 0.000042866941 (169) +  

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If you round off the values up to 4 decimal places then you get error as:

|3.1138 - 3.1137| = 0.0001

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