Based on the above:
The slope of P'Q' is = -3/2
The length of P'Q' is approximately = ![\sqrt[3]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13%7D)
<h3>What is the polygon about?</h3>
The slope of P'Q'
= -6/4 = -3/2
The length of P'Q' =
P'Q' = 
= 
= ![\sqrt[2]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B13%7D)
Therefore;
P'Q' =
P'Q' =
x ![\sqrt[2]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B13%7D)
= ![\sqrt[3]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13%7D)
Learn more about polygon from
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<h2>3</h2>
S<--->T
T<--->S
Same thing
<h2>4</h2>
Both sides a equivalent therefore both triangle areas are also equivalent
Z=1/5
Subtract 85 from both sides which gets you 25z=5.
Divide both sides by 25 which is z=5/25
Simplify which gives us the answer z=1/5.
Start by adding together the shortest two sides, 7 and 8.7 inches. Result: 15.7 inches. Because this sum is greater than the longest side, 15.4 inches, it's possible to construct a triangle, whose largest angle will be close to 180 degrees.
The slope of the line is 3/2 i believe