<span>let:
m1 = 2xy a
m2 = 2xy b
m3 = 2x2y c
since 2 and 3 have a common factor let b=2n
m1 = 2xy a
m2 = 2xy 2 n
m3 = 2x2y c
or simply
m1 = 2xy a
m2 = 2xy 2n
m3 = 2xy 2c
given that anc have no common factors</span>
Answer:
the correct answer is a
Step-by-step explanation:
Answer:
True
Step-by-step explanation:
True because if AC = BC, then the triangles are the same.
Answer:
I'll find X for you; the next step is by you.
Step-by-step explanation:
we have two similar pentagons
I will do it in 2 ways.
1.
=> 48/4x = (x+2)/x
=> 12/x = (x+2)/x
Because of pentagons so x > 0
=> 12 = x + 2 => x = 10
2.
k is unknown number
=> 4x = k.x and 48 = k.(x + 2) (x > 0)
=> k = 4 and 48 = 4.(x + 2)
=> 12 = x + 2 => x = 10
Answer:
42°
Step-by-step explanation:
AD bisects ∠CAB, which means it splits ∠CAB into two equal parts. ∠CAB equals 84°. 84° ÷ 2 = 42°.
