3 years ago

How to find the gravitational field strength of a planet?

Mathematics

1 answer:

Olenka [21]3 years ago

8 0

The gravitational field strength is g=G M/r^2

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Can someone please help me

Natalija [7]

ANSWER: $84

EXPLANATION:

We need to know the surface area of the room with the specified dimensions.

A = 2(wl + hl + hw)

w = 12
h = 8
l = 16

A = 2( (12 * 16) + (8 * 16) + (12 * 8) )

A = 2(192 + 128 + 96)

A = 2(416)

A = 832 square feet

832 / 150 = 5.546666666666667

(Round that up to the next whole number)

You need 6 gallons, or 6(14) dollars

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4 years ago

X+7=5x2 what's the answer

Helen [10]

Answer: 3

Explanation:

x + 7 = 5 x 2

you do 5(2) and get 10

plug in 10 and the equation looks like:

x + 7 = 10

from there you would subtract 7 from 7 and 10 to isolate x and get your answer of:

x = 3 :)

3 0

3 years ago

Etermine the x-intercept and y intercept of the following equations.

quester [9]

It’s c uk what I mean it’s c cuzzz

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3 years ago

Find x <br> Help me plz!!!

mariarad [96]

9514 1404 393

Answer:

x = 8

Step-by-step explanation:

Assuming the figure is a parallelogram, the diagonals bisect each other. That means ...

3x -11 = x +5

2x = 16 . . . . . . . add 11-x to both sides

x = 8 . . . . . . divide by 2

3 0

3 years ago

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He length of a rectangle is three times its width. The perimeter of the rectangle is at most 112 cm.

g100num [7]

The equation relating length to width
L = 3W
The inequality stating the boundaries of the perimeter
LW <= 112
When you plug in what L equals in the first equation into the second equation, you get
3W * W <= 112
evaluate
3W^2 <= 112
3W <= $4 \sqrt{7}$
W <= $\frac{4 \sqrt{7} }{3}$ cm

8 0

3 years ago

Read 2 more answers