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3 years ago

How to find the gravitational field strength of a planet?

Mathematics

1 answer:

Olenka [21]3 years ago

8 0

The gravitational field strength is g=G M/r^2

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List the first 4 terms of the sequence 3n² + 1

Ganezh [65]

Answer:

4, 13, 28, 49

Step-by-step explanation:

1st term = 3 × (1)² + 1 = 4

2nd term = 3 × (2)² + 1 = 13

3rd term = 3 × (3)² + 1 = 28

4th term = 3 × (4)² + 1 = 49

3 0

3 years ago

Read 2 more answers

ANSWER MY QUESTION PLEASE

mina [271]

When you plug the equation into a graphing calculator the x-intercept is -5
Or you can set the equation equal to 0 and solve for x.

6 0

4 years ago

Solve the following proportion for y.

LekaFEV [45]

Answer:

y = 110/3 or 36.6 (the 6 is infinite so make a line over it when entering the answer)

7 0

3 years ago

Prove by mathematical induction that 1+2+3+...+n= n(n+1)/2 please can someone help me with this ASAP. Thanks

Iteru [2.4K]

Let

$P(n):\ 1+2+\ldots+n = \dfrac{n(n+1)}{2}$

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

$P(1):\ 1 = \dfrac{1\cdot 2}{2}=1$

So, the base case is ok. Now, we need to assume $P(n)$ and prove $P(n+1)$ .

$P(n+1)$ states that

$P(n+1):\ 1+2+\ldots+n+(n+1) = \dfrac{(n+1)(n+2)}{2}=\dfrac{n^2+3n+2}{2}$

Since we're assuming $P(n)$ , we can substitute the sum of the first n terms with their expression:

$\underbrace{1+2+\ldots+n}_{P(n)}+n+1 = \dfrac{n(n+1)}{2}+n+1=\dfrac{n(n+1)+2n+2}{2}=\dfrac{n^2+3n+2}{2}$

Which terminates the proof, since we showed that

$P(n+1):\ 1+2+\ldots+n+(n+1) =\dfrac{n^2+3n+2}{2}$

as required

4 0

3 years ago

Which property is illustrated by the following statement?

kirza4 [7]

Associative property of addition

8 0

3 years ago