All categories

4 years ago

Factored completely, the expression 6x - x^3 - x^2 is equivalent to

Mathematics

1 answer:

Anni [7]4 years ago

4 0

Answer:

( x - 2 ) ( x + 3 )

Step-by-step explanation:

-x³ - x² + 6x

x² + x - 6

( x - 2 ) ( x + 3 )

x = -3,2

You might be interested in

Help me solve C=AB+D for B.

Mars2501 [29]

C=AB+D
C-D=AB
C/A-D/A=B

7 0

3 years ago

Use the drop-down menus to describe the key aspects of the function f(x) = –x2 – 2x – 1.

Margaret [11]

Answer: The vertex is the minimum value

The function is increasing when x<1

The function is decreasing when x>1

The domain of the function is all real numbers

The range of the function is all numbers less than it equal to 0

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A rectangular room is 6.8 meters longer than it is wide, and perimeter is 29.6 meters. Find the dimensions of the room.

GuDViN [60]

Answer:

dimensions = 10.8 X 4

Step-by-step explanation:

Breadth/ width of room = x

Length of room = 6.8 + x

perimeter = 2 ( L + B )

29.6 = 2 ( 6.8 + x + x )

29.6/2 = 6.8 + 2x

14.8 - 6.8 = 2x

8 = 2x

8/2=x

4=x

Length of room = 6.8 + x = 6.8 + 4 = 10.8 m

Breadth/ width of room = x = 4m

8 0

3 years ago

Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5

Bond [772]

Answer:

The solution to the equation system given is:

<u>x = 2</u>
<u>y = -1</u>

Step-by-step explanation:

First, we must know the equations given:

2x + 3y = 1
3x + y = 5

Following Crammer's Rule, we have the matrix form:

$\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]$

Now we solve using the determinants:

$x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2$

$y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1$

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

2x + 3y = 1
2(2) + 3(-1)= 1
4 - 3 = 1
1 = 1

And, with the second equation:

3x + y = 5
3(2) + (-1) = 5
6 - 1 = 5
5 = 5

4 0

3 years ago

What is the solution to this equation? 2x+4=16

AlekseyPX

$2x+4=16\\\\2x=12\\\\x=6$

3 0

3 years ago