Question

I will mark you as brainliest !!!!

Answer 1

Answer:

B,C

Step-by-step explanation:

$x^2+3x-6=0\\\frac{-b+\sqrt{b^2-4ac}}{2a},\frac{-b-\sqrt{b^2-4ac}}{2a}\\\frac{-3+\sqrt{3^2-4*1*(-6)}}{2*1},\frac{-3-\sqrt{3^2-4*1*(-6)}}{2*1}\\\frac{-3+\sqrt{9+24}}{2},\frac{-3-\sqrt{9+24}}{2}\\\\\frac{-3+\sqrt{33}}{2},\frac{-3-\sqrt{33}}{2}$The answer must be B and C.