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yawa3891 [41]
4 years ago
7

When adding polynomials, you may use either a horizontal or a vertical format.  Explain which format you prefer and what you vie

w as its advantages
Mathematics
1 answer:
Naddika [18.5K]4 years ago
6 0
I prefer adding polynomials horizontally because its quick to just group and add like terms. Plus you read things horizontally so it seems more natural. if you add them vertically you have to line up the like terms and place a zero where there are none.

Horizontal
5x³ + 2x² + 6 + x³ - 6x² + 3x - 4 = 6x³ - 4x² + 3x + 2

Vertical
 5x³ + 2x² + 0 + 6
+ x³ - 6x² + 3x - 4
------------------------
6x³ - 4x² + 3x + 2
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For the function given below, find a formula for the Riemann sum obtained by dividing the interval [0,5] into n equal subinterva
sergij07 [2.7K]

Given

we are given a function

f(x)=x^2+5

over the interval [0,5].

Required

we need to find formula for Riemann sum and calculate area under the curve over [0,5].

Explanation

If we divide interval [a,b] into n equal intervals, then each subinterval has width

\Delta x=\frac{b-a}{n}

and the endpoints are given by

a+k.\Delta x,\text{ for }0\leq k\leq n

For k=0 and k=n, we get

\begin{gathered} x_0=a+0(\frac{b-a}{n})=a \\ x_n=a+n(\frac{b-a}{n})=b \end{gathered}

Each rectangle has width and height as

\Delta x\text{ and }f(x_k)\text{ respectively.}

we sum the areas of all rectangles then take the limit n tends to infinity to get area under the curve:

Area=\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\Delta x.f(x_k)

Here

f(x)=x^2+5\text{ over the interval \lbrack0,5\rbrack}\Delta x=\frac{5-0}{n}=\frac{5}{n}x_k=0+k.\Delta x=\frac{5k}{n}f(x_k)=f(\frac{5k}{n})=(\frac{5k}{n})^2+5=\frac{25k^2}{n^2}+5

Now Area=

\begin{gathered} \lim_{n\to\infty}\sum_{k\mathop{=}1}^n\Delta x.f(x_k)=\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\frac{5}{n}(\frac{25k^2}{n^2}+5) \\ =\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\frac{125k^2}{n^3}+\frac{25}{n} \\ =\lim_{n\to\infty}(\frac{125}{n^3}\sum_{k\mathop{=}1}^nk^2+\frac{25}{n}\sum_{k\mathop{=}1}^n1) \\ =\lim_{n\to\infty}(\frac{125}{n^3}.\frac{1}{6}n(n+1)(2n+1)+\frac{25}{n}n) \\ =\lim_{n\to\infty}(\frac{125(n+1)(2n+1)}{6n^2}+25) \\ =\lim_{n\to\infty}(\frac{125}{6}(1+\frac{1}{n})(2+\frac{1}{n})+25) \\ =\frac{125}{6}\times2+25=66.6 \end{gathered}

So the required area is 66.6 sq units.

3 0
1 year ago
2х + 6 = 7x - 14<br> What’s the answer?
Radda [10]

Answer:

x = 4

Step-by-step explanation:

2x + 6 = 7x - 14

2x - 7x = - 14 - 6

-5x = -20

x = 4

5 0
4 years ago
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How many packs of DVDs can you buy with 150 dollars if one pack costs 15 dollars ?
erik [133]
10 not including tax
7 0
3 years ago
Amira has 3/4 of a bag of cat food .Her cat eats 1/10 of a bag per week . How many weeks will the food last ?
const2013 [10]

namely how many times does 1/10 go into 3/4?

\bf \cfrac{3}{4}\div \cfrac{1}{10}\implies \cfrac{3}{4}\cdot \cfrac{10}{1}\implies \cfrac{3}{1}\cdot \cfrac{10}{4}\implies \cfrac{3}{1}\cdot \cfrac{5}{2}\implies \cfrac{15}{2}\implies 7\frac{1}{2}

6 0
3 years ago
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Solve the equation p=8L+5w for L.
Reptile [31]
A)
p-5w=8L + 5w - 5w
p -5w=8L
(p- 5w)/8 = 8L/8
(p- 5w)/8 = L
8 0
4 years ago
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