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Ahat [919]
3 years ago
7

Why is there a 0 the quotient

Mathematics
1 answer:
Natalka [10]3 years ago
6 0

Answer:

so when you multiply zero by the divisor, you'll get zero; and you know that subtracting 0 from any number leaves it just the same.

google

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What is the mixed number for 66/35 ?
sladkih [1.3K]
66/35 = Improper Fraction
 
66 - 35 = 31
 
So, 66 can go in 31 1 time.

So 1 will be our whole number. 31 will be d numerator and 35 will be d denominator. 1 31/35
 
So, 66/35 in mixed number is 1 31/35.
 
Hope I helped ya!!! xD
7 0
3 years ago
Read 2 more answers
Which rational number is one tick mark to the left of -3/4<br> on the number line above?
abruzzese [7]

Answer:

Put it in between the 0 and -1. Put it on the last line closer to the -1 but not on the -1.

Step-by-step explanation:

This is because 3/4 in general is less than one.

6 0
3 years ago
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EASY, WILL GIVE BRAINLEIST, AND FRIEND YOU NEED TO TURN IN BY 9:40 PM
LenaWriter [7]

Answer:

4z+8-6=34

7z/4+5x=29

y to the 2nd power divided (3z)=6

6 0
3 years ago
A convex polyhedron is made of 12 congruent faces like the one shown below. What is the name of the solid? A) dodecahedron ANSWE
Anvisha [2.4K]

Answer: dodecahedron

Step-by-step explanation:

6 0
3 years ago
Point B is 2/3 the way from A(-2,5)to C(4,-4). Find the location of B
mr Goodwill [35]

well, we'll first off put the point AC in component form by simply doing a subtraction of C - A, multiply that by the fraction 2/3, and that result will get added to point A, to get point B.

\bf \textit{internal division of a segment using a fraction}\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-4})~\hfill \frac{2}{3}\textit{ of the way from }A\to C \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_2}{4}-\stackrel{x_1}{(-2)}, \stackrel{y_2}{-4}-\stackrel{y_1}{5})\implies (4+2,-9) \stackrel{\textit{component form of segment AC}}{\qquad \implies \qquad (6,-9)} \\\\[-0.35em] ~\dotfill

\bf \stackrel{~\hfill \textit{coordinates to be added to point A}} {\cfrac{2}{3}(6,-9)\implies \cfrac{2}{3}(6)~,~\cfrac{2}{3}(-9)\qquad \implies \qquad \left(4,-6\right)} \\\\\\ \stackrel{\textit{additions to point A}} {\stackrel{\textit{point A}}{(-2,5)}+\left( 4,-6\right)}\implies \left( -2+4~~,~~5-6\right) = B\implies (2~,~-1)=B

5 0
3 years ago
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