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aleksandrvk [35]
3 years ago
10

Simplify and solve this equation: 4m + 9 + 5m – 12 = 42.

Mathematics
2 answers:
Anton [14]3 years ago
8 0
So first separate the expressions and numbers so it will be easier to solve. expressions on the left and numbers on the right or vice versa. (be carefull with the addition and subtraction signs)
4m+9+5m-12=42
5m+4m=42+12-9
9m=45
m=5

Therefore the answer is C. m=5
FinnZ [79.3K]3 years ago
5 0
4m + 9 + 5m - 12 = 42
9m + 9 -12 = 42
9m -3 = 42
9m = 42 + 3 
9m = 45 
m= 45/9
m= 5
Answer is C. 
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The length of the sides of a triangle are x, 2x+2, and 13. If the perimeter of the triangle is 30, what is the value of x?
scZoUnD [109]

Add all the sides up to equal 30 in an equation because you are given the perimeter. The perimeter is the length around a two dimensional shape. This means the perimeter is the length of all the side lengths added together.

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Combine like terms.

3x + 15 = 30

Subtract 15 from both sides.

3x = 15

Divide both sides by 3.

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3 years ago
Janine graphs these two lines and finds that they intersect.
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2 years ago
Solve the system of equations by graphing <br> y=4x-3 <br> y=-2x+3
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12What mistake did the student make when solvingtheir two-step equation?(a)b) If correctly solved what should the value of be?
mixas84 [53]

Given the equation:

\frac{x}{6}+3=-18

(a) You can identify that the student applied the Subtraction Property of Equality by subtraction 3 from both sides of the equation:

\frac{x}{6}+3-(3)=-18-(3)

However, the student made a mistake when adding the numbers on the right side.

Since you have two numbers with the same sign on the right side of the equation, you must add them, not subtract them and use the same sign in the result. Then, the steps to add them are:

- Add their Absolute values (their values without the negative sign).

- Write the sum with the negative sign.

Then:

\frac{x}{6}=-21

(b) The correct procedure is:

1. Apply the Subtraction Property of Equality by subtracting 3 from both sides (as you did in the previous part):

\begin{gathered} \frac{x}{6}+3-(3)=-18-(3) \\  \\ \frac{x}{6}=-21 \end{gathered}

2. Apply the Multiplication Property of Equality by multiplying both sides of the equation by 6:

\begin{gathered} (6)(\frac{x}{6})=(-21)(6) \\  \\ x=-126 \end{gathered}

Hence, the answers are:

(a) The student made a mistake by adding the numbers -18 and -3:

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(b) The value of "x" should be:

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