Plz help Arithmetic Sequence

Anestetic [448]

F(-11/5)=5(-11/5)+6
f(-11/5) = -11+6
<span>f(-11/5) = -5
Hope this helps!</span>

6 0

3 years ago

What are the coordinates of the vertex of the graph of f(x)=4|x+6|? Enter your answer as an ordered pair without parentheses in

Marina86 [1]

Is this what you're needing?

6 0

3 years ago

Read 2 more answers

Which is equivalent to x^3 y^-7

PilotLPTM [1.2K]

For this case we must find an expression equivalent to:

$x ^ 3 * y ^ {- 7}$

By definition of power properties we have to meet:

$a ^ {-1} = \frac {1} {a ^ 1} = \frac {1} {a}$

Then, we can rewrite the expression as:

$x ^ 3 * \frac {1} {y ^ 7} =\\\frac {x ^ 3} {y ^ 7}$

Answer:

$\frac {x ^ 3} {y ^ 7}$

8 0

2 years ago

determine the maximum or minimum of the quadratic function. express your answer in the form (x,y) and using decimals rounded to

kolezko [41]

We are given the following quadratic equation

$f(x)=2x^2+7x-10$

The vertex is the maximum/minimum point of the quadratic equation.

The x-coordinate of the vertex is given by

$h=-\frac{b}{2a}$

Comparing the given equation with the general form of the quadratic equation, the coefficients are

a = 2

b = 7

c = -10

$h=-\frac{b}{2a}=-\frac{7}{2(2)}=-\frac{7}{4}=-1.75$

The y-coordinate of the vertex is given by

$\begin{gathered} f(x)=2x^2+7x-10 \\ f(-1.75)=2(-1.75)^2+7(-1.75)-10 \\ f(-1.75)=2(3.0625)^{}-12.25-10 \\ f(-1.75)=6.125^{}-12.25-10 \\ f\mleft(-1.75\mright)=-16.13 \end{gathered}$

This means that we have a minimum point.

Therefore, the minimum point of the given quadratic equation is

$(-1.75,-16.13)$

7 0

6 months ago

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State the linear programming problem in mathematical terms, identifying the objective function and the constraints. A firm makes

Sedbober [7]

Answer:

Maximum profit at (3,0) is $27.

Step-by-step explanation:

Let quantity of products A=x

Quantity of products B=y

Product A takes time on machine L=2 hours

Product A takes time on machine M=2 hours

Product B takes time on machineL= 4 hours

Product B takes time on machine M=3 hours

Machine L can used total time= 8hours

Machine M can used total time= 6hours

Profit on product A= $9

Profit on product B=$7

According to question

Objective function Z= $9x+7y$

Constraints:

$2x+3y\leq 6$

$2x+4y\leq 8$

Where $x\geq 0, y\geq 0$

I equation $2x+3y\leq 6$

I equation in inequality change into equality we get

$2x+3y=6$

Put x=0 then we get

y=2

If we put y=0 then we get

x= 3

Therefore , we get two points A (0,2) and B (3,0) and plot the graph for equation I

Now put x=0 and y=0 in I equation in inequality

Then we get $0\leq 6$

Hence, this equation is true then shaded regoin is below the line .

Similarly , for II equation

First change inequality equation into equality equation

we get $2x+4y=8$

Put x= 0 then we get

y=2

Put y=0 Then we get

x=4

Therefore, we get two points C(0,2)a nd D(4,0) and plot the graph for equation II

Point A and C are same

Put x=0 and y=0 in the in inequality equation II then we get

$0\leq 8$

Hence, this equation is true .Therefore, the shaded region is below the line.

By graph we can see both line intersect at the points A(0,2)

The feasible region is AOBA and bounded.

To find the value of objective function on points

A (0,2), O(0,0) and B(3,0)

Put A(0,2)

Z= $9\times 0+7\times 2=14$

At point O(0,0)

Z=0

At point B(3,0)

Z= $9\times3+7\times0=27$

Hence maximum value of z= 27 at point B(3,0)

Therefore, the maximum profit is $27.

6 0

3 years ago