Answer:
B. Vertical angles are congruent
Step-by-step explanation:
The instructions are to prove that ∠ANR and ∠VNE are congruent, and ∠ANR and ∠VNE are vertical angles.
I hope this helps :)
Answer:
B. No.
Step-by-step explanation:
We have been given 3 side lengths 7 ft, 12 ft, 17 ft. We are asked to determine, whether the given set of lengths can form a right triangle or not.
We will use Pythagoras theorem to solve our given problem, which states that the square of hypotenuse of a right triangle is equal to the sum of squares of two legs of right triangle.
Since the sum of squares of both legs is less than square of hypotenuse, therefore, the given set of lengths can not be the side lengths of a right triangle.
Answer:
JK = 6 units
3 equal parts
-7
Step-by-step explanation:
The total distance for JK = -3 - -9 = -3+9 = 6
The length of JK = 6 units
ratio 1:2 total is 3
Divide JK into 3 equal parts
When we divide into 3 equal parts, we split the line at -7 and -5
To have the ratio at 1 to 2 take the 1st point -7
Recall that
cos(A + B) = cos(A) cos(B) - sin(A) sin(B)
sin(A + B) = sin(A) cos(B) + cos(A) sin(B)
By definition of cotangent,
cot(A + B) = 1 / tan(A + B) = cos(A + B) / sin(A + B)
and by applying the identities above,
cot(A + B) = (cos(A) cos(B) - sin(A) sin(B)) / (sin(A) cos(B) + cos(A) sin(B))
Now, multiply the expression on the right by 1/(sin(A) sin(B)) to get
cot(A + B) = (cot(A) cot(B) - 1) / (cot(B) + cot(A))
Given tan(A) = 1/4 and tan(B) = 1/5, we have cot(A) = 4 and cot(B) = 5, so that
cot(A + B) = (4×5 - 1) / (5 + 4) = 19/9