In the problems A-F, You multiply each of the numbers by itself. Like 9²=9×9=81
3³=3×3×3=27 6³=6×6×6=216 and so on for the other problems
G-I is 36=6² 100=10² and so on the cube is the same except you multiply the number three times by itself. I hope this helped a bit. Just ask if you still don't understand.
The solution to the equation is p = 1/3 and q = undefined
<h3>How to solve the equation?</h3>
The equation is given as:
p^2 - 2qp + 1/q = (p - 1/3)
The best way to solve the above equation is by the use of a graphing calculator i.e. graphically
However, it can be solved algebraically too (to some extent)
Recall that the equation is given as:
p^2 - 2qp + 1/q = (p - 1/3)
Split the equation
So, we have
p^2 - 2qp + 1/q = 0
p - 1/3 = 0
Solve for p in p - 1/3 = 0
p = 1/3
Substitute p = 1/3 in p^2 - 2qp + 1/q = 0
So, we have
(1/3)^2 - 2q(1/3) + 1/q = 0
This gives
1/9 - 2/3q + 1/q = 0
This gives
2/3q + 1/q = -1/9
Multiply though by q
So, we have
2/3q^2 + 1 = -1/9q
Multiply through by 9
6q^2 + 9 = -q
So, we have
6q^2 + q + 9 = 0
Using the graphing calculator, we have
q = undefined
Hence. the solution to the equation is p = 1/3 and q = undefined
Read more about equations at:
brainly.com/question/13763238
#SPJ1
√-1=i
13-√-18=
13-√(-1)(18)=
13-(√-1)(√18)=
13-(i)(3√2)=
13-3i√2
Answer:
They are even numbers (divisible by two)
Step-by-step explanation:
The number column starts from 2 and is incremented by two for every number in the column. The remainder of the division of each number in the sequence is zero and the result of the division is sequence 1,2,3,4,5,6,7...
Therefore, the numbers in the column are even numbers.
2 tables. Table 1 is titled Population data with entries 2, 4, 8, 5, 1, 1, 10, 5, 4, 2, 3, 3. Table 2 is titled Sample data with
alekssr [168]
Answer: //The mean of the population is 4
//The mean of the population is 3.25
//The difference between the mean of the sample and the mean of the population is 0.75
Step-by-step explanation: EGDEUNITY
