Answer:
(a)-6 and 24
(b)-12 and 12.
Step-by-step explanation:
Using the mean value theorem,
Suppose that f is a function which is continuous on a closed interval [a, b] and differentiable on an open interval (a, b), then there
exists a number c in (a, b) so that
for every closed interval [a,b].
−2≤f′(x)≤4 and f(2)=4
First, we determine the largest and smallest possible value for f(7).
In the Interval [2,7],
Since −2≤f′(x)≤4
Recall that: f(2)=4
The greatest and least value are 24 and -6 respectively.
Similarly for f(-2)
In the Interval [-2,2],
Since −2≤f′(x)≤4
Recall that: f(2)=4
Dividing all through by negative
The greatest and least value are 12 and -12 respectively.
2,300 L—> 22L—>3,000ml—>2L—>500ml. I first started with the greatest amount of liters and then went to the least amount. For the 3000ml it’s 3 liter because there are 1,000 ml per liters and 3 is greater then 2.
Answer:
Infinitely many solutions.
Step-by-step explanation:
2 (n - 1) + 4n = 2 (3n - 1) Let's simplify this to solve it.
2n - 2 + 4n = 6n - 2 Distribute 2(n-1) and 2(3n-1)
2n + 4n - 2 = 6n - 2 Rearrange the left side of the equation.
6n - 2 = 6n - 2 Add 2n + 4n.
-6n -6n Subtract 6n from both sides.
-2 = -2? Yes, -2 equals -2.
Therefore, the answer is infinitely many solutions, meaning that <em>n </em>can be any real number.
Answer is A
Yes because each x value has exactly one corresponding y value
It’s D, as you would multiply 4 and 3, and put it over 5.
