1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pychu [463]
3 years ago
12

I don't understand if my problem is diameter or radius, it has two lines from the center but one is going to the right and one i

s down. is this radius or diameter?

Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0
I hope this helps you





diameter=2r

You might be interested in
A car traveling at 65 mph leaves a 25 foot skid mark. What is the ratio of the speed (mph) to length of skid mark (feet)? Give y
liq [111]

Remark

The ratio is 65 mph / 25 feet It's an odd unit but that's what it is. It does not change.

Divide top and bottom by 5

65 ÷ 5 = 13

25 ÷ 5 = 5

So the ratio in simplest form is 13/5.

8 0
4 years ago
Is 3/5 bigger than 65%
Effectus [21]
If we think 1(5/5) is 100%
3/5=100×3/5=60%
60%is less than 65%
5 0
3 years ago
Line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate
Murljashka [212]

Answer:

B. \frac{25}{64}

Step-by-step explanation:

Please find the attachment.  

We have been given that line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate of 2 and point L has a coordinate of 8.

The probability that the first point is positioned on JL would be \frac{10}{16} as there are total 10 points on JL as L is at point 8 and J is at point -2 so (8--2=8+2=10). Total number of points on the number line JM is (14--2=14+2=16)  

The probability that second point is not placed on KL would be:

P(\text{The point is not on KL)}=1-\text{probability that point is on KL}

P(\text{The point is not on KL)}=1-\frac{\text{Total points on KL}}{\text{Total points on JM}}

P(\text{The point is not on KL)}=1-\frac{(8-2)}{16}

P(\text{The point is not on KL)}=1-\frac{6}{16}

P(\text{The point is not on KL)}=\frac{16-6}{16}

P(\text{The point is not on KL)}=\frac{10}{16}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{10}{16}\times \frac{10}{16}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{5}{8}\times \frac{5}{8}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{25}{64}

Therefore, our desired probability will \frac{25}{64} and option B is the correct choice.

5 0
3 years ago
Please help me it takes do long to do this please
Alexxandr [17]

Answer:

Step-by-step explanation:

a. (I) x = 65

(ii) vertically opposite angles are equal.

b. (i) 71 degrees

(ii) alternate interior angles are equal

c. (i) z = 180 - 71 = 109 degrees

(ii) angles on a line add up to 180 degrees

<h3>Hope this helps</h3>
6 0
4 years ago
Read 2 more answers
What is the equation of the graph in slope intercept form
Crank

Answer:

y=1/4x-4

Step-by-step explanation:

slope is 1/4 and the y intercept is -4

3 0
3 years ago
Other questions:
  • What is government as a subject<br>​
    13·1 answer
  • To attend a selective college, how many years of high school math. Must you complete
    6·2 answers
  • Wats the most 6/9 or 11/13
    9·2 answers
  • Plz explain why plz and thx asap
    7·1 answer
  • Tresa soccer team I feel six water coolers before the game it's a water cooler hold 9 L to the water how many liters of water do
    6·2 answers
  • Can you help me solve this?
    6·1 answer
  • Help!!!! Me !! ASAP !!!!! Give me the perimeter and with explanation!!! Pls!!!
    10·1 answer
  • XZ¯¯¯¯¯¯¯¯ is the bisector of ∠WXY. If m∠WXY=9x+12 and m∠YXZ=6x−6, what is m∠WXZ?
    13·1 answer
  • If f(x)= x-5 then match the following ​
    9·1 answer
  • Please Hurry). Which answer describes the type of sequence? 3,4,7,11. A) geometric, B) arithmetic, C) neither arithmetic nor geo
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!