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lapo4ka [179]
4 years ago
11

The communication Diagram contains:

SAT
1 answer:
Bezzdna [24]4 years ago
3 0

Explanation:

I want to say your answer is (D)- b and c.

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The first five multiples for the numbers 4 and 6 are shown below. Multiples of 4: 4, 8, 12, 16, 20,. . . Multiples of 6: 6, 12,
blagie [28]

Answer:

12

Explanation:

12 is the first number that has come on both lists so 12 is the answer

8 0
3 years ago
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Listed following are several objects in the solar system. Rank these objects from left to right based on their distance from the
Kitty [74]

The list is not found here but planets are ordered from closest to farthest to the Sun as Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune.

<h3>What are the closest planets to the Sun?</h3>

The closest planets to the Sun are rocky planets, i.e., Mercury, Venus, Earth and Mars.

Conversely, the farthest planets to the Sun are gaseous planets, i.e., Jupiter, Saturn, Uranus, and Neptune.

In conclusion, the list is not found here but planets are ordered from closest to farthest to the Sun as Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune.

Learn more about rocky planets here:

brainly.com/question/17428928

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4 0
2 years ago
Formal outline of becoming a landscape architect brainly
Archy [21]

Answer:

what can you please explain better for me I do not understand

8 0
3 years ago
suppose you push a hockey puck of mass m across frictionless ice for a time 1.0 s, starting from rest, giving the puck speed v a
saul85 [17]

Answer: Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.

Explanation:

Let a Force pushes the hockey puck of mass m.

Then acceleration, a= \frac{F}{m}a=mF

From the equation of motion,

\begin{gathered}\➪ v=u+at\\ v=0+\frac{F}{m}\Delta t\end{gathered}⇒v=u+atv=0+mFΔt ......(1)

In the second case, when mass is 2m, then acceleration,

a'=\frac{F}{2m}a′=2mF

and t' is the time taken.

The final speed is v,

\begin{gathered}\➪ v=0+ a't'\\ \➪ \frac {F}{m}\Delta t=\frac{F}{2m}t'\\ \➪ t'= 2\Delta t\end{gathered}⇒v=0+a′t′⇒mFΔt=2mFt′⇒t′=2Δt using equation (1)

Hence, it would take two times the previous amount of time to push the pluck of double mass.

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3 0
3 years ago
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I need help.... with this
Helen [10]

Answer:

1: Balanced forces will cause no change in the speed of an object

2: Balanced forces do not cause a change in the speed of a moving object.

3: For unbalanced forces you can say the opposite of the above.

Explanation:

7 0
3 years ago
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