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3 years ago

The angle of elevation from L to k measures 55 degrees If JK=26 find JL round your answer to the nearest tenth

Mathematics

1 answer:

TiliK225 [7]3 years ago

6 0

If the entire angle is equal to 55 degrees than JL would equal 29

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What kind of triangle is this!!! Please Help!!!

Arisa [49]

Answer:

Right Isosceles

Step-by-step explanation:

First, let's see if this triangle is Acute, Obtuse or Right.

We see that PB and QB are perpendicular lines, meaning that they form a right angle. Therefore, triangle PQB is a right triangle.

Next, let's see if this triangle is equilateral, isosceles or scalene. PB and QB are congruent side lengths but PQ is not congruent to either PB or QB. Therefore, because two of the side lengths are congruent to each other and one is not, then triangle PQB is a isosceles triangle.

In conclusion, triangle PQB can be categorized as a right isosceles triangle.

Hope this helps!

3 0

3 years ago

Triangle BCD is equivalent AG=1.find the perimeter of BCD

Ymorist [56]

AG=1 => BG=3 => CG=sqrt3 => CD = 2sqrt3 => perimeter = 3*CD= 6sqrt3

4 0

4 years ago

Convert 7/11 to a percent. round the answer to the nearest hundredth

pychu [463]

<h3>Answer:</h3>

63.64%

<h3>Step-by-step explanation:</h3>

7/11 = 7/11 × 100% = (700/11)% ≈ 63.64%

_____

<em>Comment on fractions involving 11</em>

1/11 is the 2-digit repeating decimal 0.09090909...

So, any multiple of 1/11 is a 2-digit repeating decimal with the two digits being the numerator times 9.

Here, we have 7/11, so the 2-digit repeat is 7·9 = 63. That is ...

... 7/11 = 0.63636363...

3 0

3 years ago

use the general slicing method to find the volume of The solid whose base is the triangle with vertices (0 comma 0 ), (15 comma

lyudmila [28]

Answer:

volume V of the solid

$\boxed{V=\displaystyle\frac{125\pi}{12}}$

Step-by-step explanation:

The situation is depicted in the picture attached

(see picture)

First, we divide the segment [0, 5] on the X-axis into n equal parts of length 5/n each

[0, 5/n], [5/n, 2(5/n)], [2(5/n), 3(5/n)],..., [(n-1)(5/n), 5]

Now, we slice our solid into n slices.

Each slice is a quarter of cylinder 5/n thick and has a radius of

-k(5/n) + 5 for each k = 1,2,..., n (see picture)

So the volume of each slice is

$\displaystyle\frac{\pi(-k(5/n) + 5 )^2*(5/n)}{4}$

for k=1,2,..., n

We then add up the volumes of all these slices

$\displaystyle\frac{\pi(-(5/n) + 5 )^2*(5/n)}{4}+\displaystyle\frac{\pi(-2(5/n) + 5 )^2*(5/n)}{4}+...+\displaystyle\frac{\pi(-n(5/n) + 5 )^2*(5/n)}{4}$

Notice that the last term of the sum vanishes. After making up the expression a little, we get

$\displaystyle\frac{5\pi}{4n}\left[(-(5/n)+5)^2+(-2(5/n)+5)^2+...+(-(n-1)(5/n)+5)^2\right]=\\\\\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2$

But

$\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2=\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}((5/n)^2k^2-(50/n)k+25)=\\\\\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)$

we also know that

$\displaystyle\sum_{k=1}^{n-1}k^2=\displaystyle\frac{n(n-1)(2n-1)}{6}$

and

$\displaystyle\sum_{k=1}^{n-1}k=\displaystyle\frac{n(n-1)}{2}$

so we have, after replacing and simplifying, the sum of the slices equals

$\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)=\\\\=\displaystyle\frac{5\pi}{4n}\left(\displaystyle\frac{25}{n^2}.\displaystyle\frac{n(n-1)(2n-1)}{6}-\displaystyle\frac{50}{n}.\displaystyle\frac{n(n-1)}{2}+25(n-1)\right)=\\\\=\displaystyle\frac{125\pi}{24}.\displaystyle\frac{n(n-1)(2n-1)}{n^3}$

Now we take the limit when n tends to infinite (the slices get thinner and thinner)

$\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}\displaystyle\frac{n(n-1)(2n-1)}{n^3}=\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}(2-3/n+1/n^2)=\\\\=\displaystyle\frac{125\pi}{24}.2=\displaystyle\frac{125\pi}{12}$

and the volume V of our solid is

$\boxed{V=\displaystyle\frac{125\pi}{12}}$

3 0

3 years ago

Mark is building two separate pig-pens. The width of pig-pen A is w. The length of pig-pen A is 4 feet longer than its width. Th

Juliette [100K]

Answer:

The width of pen A is 7 feet,

The Length of Pen A is 11 feet,

The width of Pen B is 6 feet,

The Length of Pen B is 12 feet

Step-by-step explanation:

The width of pen A is 7 feet,

The Length of Pen A is 7 + 4 = 11 feet,

The width of Pen B is 7+4-5 = 6 feet,

The Length of Pen B is 2*(7+4-5) = 12 feet

$w+w+w+w+4+4=(w+4-5)+(w+4-5) +2*(w+4-5)+2*(w+4-5)\\4w+8=6w-6\\14=2w\\w=7\\$

8 0

3 years ago