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goldenfox [79]
3 years ago
10

What is 19.2x10^9 minutes in hours

Mathematics
1 answer:
maria [59]3 years ago
4 0

Answer:

19.2×10^9 =320000000

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find the t values that form the boundaries of the critical region for a two-tailed test with a=.05 for n=6 n=12
AlexFokin [52]

Answer:

n=6

"=T.INV(1-0.025,5)", and we got the critical values given by: t_{critical}=\pm 2.5706  

n=12

"=T.INV(1-0.025,11)", and we got the critical values given by: t_{critical}=\pm 2.201  

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

For n=6

In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking on the t distribution with df=n-1=6-1=5 degrees of freedom, a value that accumulates 0.05/2=0.025 of the area on each tail. We can use excel or a table to find it, for example the code in Excel is:  

"=T.INV(1-0.025,5)", and we got the critical values given by: t_{critical}=\pm 2.5706  

For n=12  

In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking on the t distribution with df=n-1=12-1=11 degrees of freedom, a value that accumulates 0.05/2=0.025 of the area on each tail. We can use excel or a table to find it, for example the code in Excel is:  

"=T.INV(1-0.025,11)", and we got the critical values given by: t_{critical}=\pm 2.201  

3 0
4 years ago
A zoo is building a new large-cat exhibit. Part of the space will be used for lions and part for leopards. The exhibit will have
Fittoniya [83]

The equations for the expenses for maintaining 4 lions and 4 leopards in the new large-cat exhibit are as follows:

                             Lions                  Leopard

Equations       4x = 32,000         4y = 24,000

<h3>What is an equation?</h3>

An equation is a mathematical statement that shows the values of two mathematical expressions are equal.

An equation is made up of two mathematical expressions connected by an equal sign.

<h3>Data and Calculations:</h3>

Annual expenses for lion per unit, x = $8,000

Annual expenses for leopard per unit, y = $6,000

Total number of larget-cats required = 8

Let the cost of maintaining 4 lions = 4x

Let the cost of maintaining 4 leopards = 4y

Total cost for 4 lions = $32,000 (8,000 x 4)

Total cost for 4 leopards = $24,000 (6,000 x 4)

Total cost for eight large cats per year = $56,000 ($32,000 + $24,000)

Equation for lions, 4x = 32,000

Equation for leopards, 4y = 24,000

The total costs for maintaining eight large cats in all will be <u>$56,000</u> per year.

Thus, the equations for the expenses for maintaining 4 lions and 4 leopards in the new large-cat exhibit are <u>4x = 32,000</u> and <u>4y = 24,000</u>, respectively.

Learn more about equations at brainly.com/question/13763238

#SPJ1

5 0
2 years ago
What are possible outcome of a spin of the spinner
Crank

Answer:

Step-by-step explanation:

it would depend on how many numbers are on the spinner like if their is 6 numbers on the spinner and if your trying to get a 4 then it would be 1/6.

Hope my answer has helped you!

8 0
3 years ago
The equation of a circle is x2+y2−12x+6y+20=0 .
Rufina [12.5K]

Answer:

The radius is r=5 units

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

(x-h)^{2}+(y-k)^{2}=r^{2}

where

(h,k) is the center and r is the radius

we have

x^{2}+y^{2}-12x+6y+20=0

Convert to standard form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}-12x)+(y^{2}+6y)=-20

Complete the square twice. Remember to balance the equation by adding the same constants to each side

(x^{2}-12x+36)+(y^{2}+6y+9)=-20+36+9

(x^{2}-12x+36)+(y^{2}+6y+9)=25

Rewrite as perfect squares

(x-6)^{2}+(y+3)^{2}=5^{2}

therefore

The center is the point (6,-3) and the radius is r=5 units

8 0
3 years ago
=
chubhunter [2.5K]

Answer:

350 tickets

Step-by-step explanation:

643-57=586

586/2=293

293+57=350

6 0
2 years ago
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