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NARA [144]
3 years ago
5

What are two cases for solving |x|

Mathematics
1 answer:
sleet_krkn [62]3 years ago
7 0

Answer:

hope this helps you. If you can't understand. If you have any questions please feel free to ask

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Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
3 years ago
What is 56 divided by 8
aleksklad [387]

56 ÷ 8 = 7

8 goes into 56 7 times

Hope this helps

-AaronWiseIsBae

8 0
3 years ago
Read 2 more answers
What is the value of 14 – 2 • 3 + 42?<br><br> someone help me understand
xxMikexx [17]

Based on PEMDAS, in this expression, we need to do multiplication first, which is 2 times 3, which is 6. Now, the expression is 14-6+42. 14-6 is 8, and 8+42 is 50, so the answer is 50.

Hope this helps!

8 0
3 years ago
Read 2 more answers
Which of the following Illusions the truth value of given statements ? 5 is less than 7 or 7 is less than 12.
Burka [1]
It's the first answer it's true true
3 0
3 years ago
Read 2 more answers
 A coat that originally sold for $369.00 is on sale at a 40% discount? How much will you pay for the coat? 
zaharov [31]
We calculate 40% from 369,00 $, this is discount

40%*369=\frac{40}{100}*369= 147,60

After sale coat costs 147,60 less so:

369 -147,60=221,40 $

Now I will pay for the coat 221,40$.
3 0
3 years ago
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