Answer:
Part A) 3/5 is the total number of shirts remaining on display after selling 2/5
Part B)
(All real whole numbers greater than or equal to 200 shirts)
Part C) Initially on display were the amount of 200 or more shirts
Step-by-step explanation:
Let
x-------> total number of shirts on display
we know that
The inequality that represent the situation is
![(1-\frac{2}{5})x+30 \geq 150](https://tex.z-dn.net/?f=%281-%5Cfrac%7B2%7D%7B5%7D%29x%2B30%20%5Cgeq%20150)
![(\frac{3}{5})x+30 \geq 150](https://tex.z-dn.net/?f=%28%5Cfrac%7B3%7D%7B5%7D%29x%2B30%20%5Cgeq%20150)
Part A) Explain what 3/5 means in the inequality
3/5 is the total number of shirts remaining on display after selling 2/5
Part B) Solve the inequality
we have
![(\frac{3}{5})x+30 \geq 150](https://tex.z-dn.net/?f=%28%5Cfrac%7B3%7D%7B5%7D%29x%2B30%20%5Cgeq%20150)
Subtract 30 both sides
![(\frac{3}{5})x \geq 150-30](https://tex.z-dn.net/?f=%28%5Cfrac%7B3%7D%7B5%7D%29x%20%5Cgeq%20150-30)
![(\frac{3}{5})x \geq 120](https://tex.z-dn.net/?f=%28%5Cfrac%7B3%7D%7B5%7D%29x%20%5Cgeq%20120)
Multiply by 5/3 both sides
![x \geq 120(5/3)](https://tex.z-dn.net/?f=x%20%5Cgeq%20120%285%2F3%29)
![x \geq 200\ shirts\ on\ display](https://tex.z-dn.net/?f=x%20%5Cgeq%20200%5C%20shirts%5C%20on%5C%20display)
Part C) Explain what the solution means in the situation
1) Initially on display were the amount of 200 or more shirts
2) 2/5 were sold and 120 or more shirts were left on display.
3) The store brought out another 30 shirts from the stockroom and placed them on display, for a total of 150 shirts or more on display