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ivolga24 [154]
3 years ago
14

A lumber company is making boards that are 2697.0 millimeters tall. If the boards are too long they must be trimmed, and if they

are too short they cannot be used. A sample of 25 boards is made, and it is found that they have a mean of 2697.4 millimeters with a standard deviation of 10.0 . Is there evidence at the 0.1 level that the boards are either too long or too short? Assume the population distribution is approximately normal.
a. Determine the decision rule for rejecting the null hypothesis.
b. Make the decision to reject or fail to reject the null hypothesis.
Mathematics
1 answer:
navik [9.2K]3 years ago
6 0
A is your answer because when it says assume the population that means that you need to figure out what isn’t he hypothesis
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Indicate whether the statement is true of false.
yawa3891 [41]

The statement is false, as the system can have no solutions or infinite solutions.

<h3>Is the statement true or false?</h3>

The statement says that a system of linear equations with 3 variables and 3 equations has one solution.

If the variables are x, y, and z, then the system can be written as:

a_1*x + b_1*y + c_1*z = d_1\\\\a_2*x + b_2*y + c_2*z = d_2\\\\a_3*x + b_3*y + c_3*z = d_3

Now, the statement is clearly false. Suppose that we have:

a_1 = a_2 = a_3\\b_1 = b_2 = b_3\\c_1 = c_2 = c_3\\\\d_1 \neq d_2 \neq  d_3

Then we have 3 parallel equations. Parallel equations never do intercept, then this system has no solutions.

Then there are systems of 3 variables with 3 equations where there are no solutions, so the statement is false.

If you want to learn more about systems of equations:

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2 years ago
Match the vocabulary word with the correct definition.
svetlana [45]

Answer:

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Step-by-step explanation:

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3 years ago
Let the number of chocolate chips in a certain type of cookie have a Poisson distribution. We want the probability that a cookie
ludmilkaskok [199]

Answer:

\lambda \geq 6.63835

Step-by-step explanation:

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Let X the random variable that represent the number of chocolate chips in a certain type of cookie. We know that X \sim Poisson(\lambda)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda

E(X)=\mu =\lambda

On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:

P(X\geq 2)=1-P(X

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-\lambda} \lambda^0}{0!}=e^{-\lambda}

P(X=1)=\frac{e^{-\lambda} \lambda^1}{1!}=\lambda e^{-\lambda}

And replacing we have this:

P(X\geq 2)=1-[P(X=0)+P(X=1)]=1-[e^{-\lambda} +\lambda e^{-\lambda}[]

P(X\geq 2)=1-e^{-\lambda}(1+\lambda)

And we want this probability that at least of 99%, so we can set upt the following inequality:

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And now we can solve for \lambda

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Applying natural log on both sides we have:

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ln(0.01) \geq -\lambda+ln(1+\lambda)

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Thats a no linear equation but if we use a numerical method like the Newthon raphson Method or the Jacobi method we find a good point of estimate for the solution.

Using the Newthon Raphson method, we apply this formula:

x_{n+1}=x_n -\frac{f(x_n)}{f'(x_n)}

Where :

f(x_n)=\lambda -ln(1+\lambda)+ln(0.01)

f'(x_n)=1-\frac{1}{1+\lambda}

Iterating as shown on the figure attached we find a final solution given by:

\lambda \geq 6.63835

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The answer to the question

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Step-by-step explanation:

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