These are two questions and two answers.
1) Problem 17.
(i) Determine whether T is continuous at 6061.
For that you have to compute the value of T at 6061 and the lateral limits of T when x approaches 6061.
a) T(x) = 0.10x if 0 < x ≤ 6061
T (6061) = 0.10(6061) = 606.1
b) limit of Tx when x → 6061.
By the left the limit is the same value of T(x) calculated above.
By the right the limit is calculated using the definition of the function for the next stage: T(x) = 606.10 + 0.18 (x - 6061)
⇒ Limit of T(x) when x → 6061 from the right = 606.10 + 0.18 (6061 - 6061) = 606.10
Since both limits and the value of the function are the same, T is continuous at 6061.
(ii) Determine whether T is continuous at 32,473.
Same procedure.
a) Value at 32,473
T(32,473) = 606.10 + 0.18 (32,473 - 6061) = 5,360.26
b) Limit of T(x) when x → 32,473 from the right
Limit = 5360.26 + 0.26(x - 32,473) = 5360.26
Again, since the two limits and the value of the function have the same value the function is continuos at the x = 32,473.
(iii) If T had discontinuities, a tax payer that earns an amount very close to the discontinuity can easily approach its incomes to take andvantage of the part that results in lower tax.
2) Problem 18.
a) Statement Sk
You just need to replace n for k:
Sk = 1 + 4 + 7 + ... (3k - 2) = k(3k - 1) / 2
b) Statement S (k+1)
Replace
S(k+1) = 1 + 4 + 7 + ... (3k - 2) + [ 3 (k + 1) - 2 ] = (k+1) [ 3(k+1) - 1] / 2
Simplification:
1 + 4 + 7 + ... + 3k - 2+ 3k + 3 - 2] = (k + 1) (3k + 3 - 1)/2
k(3k - 1)/ 2 + (3k + 1) = (k + 1)(3k+2) / 2
Do the operations on the left side and you will find it can be simplified to k ( 3k +1) (3 k + 2) / 2.
With that you find that the left side equals the right side which is a proof of the validity of the statement by induction.
Answer:
Vertex: (- 2, -1)
axis of symmetry: x= - 2
Step-by-step explanation:
f(x)=x^2+4x+3
f(x)=(x^2+4x+4)+3-4.......complete the square
f(x)=(x+2)^2-1...................write in vertex form
0.11 is the least amount.
A zero coupon bond is a type of bond that is sold below its
face value but pays no interest. At maturity, Arthur will be able to have
$5,000 but he paid $4,000 for it. Therefore, he was able to earn $1,000 ($5,000
- $4,000) from the bond.
Answer:
- Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.
Step-by-step explanation:
<u>Given expressions</u>
- 4x - x + 5 = 3x + 5
- 8 - 3x - 3 = -3x + 5
Compared, we see the expressions are different as 3x and -3x have different coefficient
<u>Answer options</u>
Both expressions should be evaluated with one value. If the final values of the expressions are both positive, then the two expressions must be equivalent.
- Incorrect. Positive outcome doesn't mean equivalent
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Both expressions should be evaluated with one value. If the final values of the expressions are the same, then the two expressions must be equivalent.
- Incorrect. There are 2 values- variable and constant
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Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are positive, then the two expressions must be equivalent.
- Incorrect. Positive outcome doesn't mean equivalent.
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Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.
