All categories

3 years ago

If g(x) = 5x + 16; then g(-2) =

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

5 0

Answer:

Step-by-step explanation:

g(x)= 5x + 16

g(x)= 5(-2) + 16

g(x)= -10 + 16

g(x)= 6

You might be interested in

Find the midpoint of the line segment joining points A and B. A(2,- 7); B(2,3)

Ad libitum [116K]

Answer: (2, -2)

Step-by-step explanation:

$\left(\frac{2+2}{2}, \frac{3-7}{2} \right)=(2,-2)$

8 0

1 year ago

Read 2 more answers

(Please answer ASAP) (Thank you <3) What is the relative frequency for Group A.

frosja888 [35]

The answer is D, I think so

8 0

2 years ago

Read 2 more answers

⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden

fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = $\frac{354}{1219}$

n = sample of US adults = 1291

p = population proportion of adults

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

significance level are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]

= [ $\frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ , $\frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ ]

= [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0

3 years ago

Patriciodeposits $500 in the same account that pays a 1.5% simple interest he does not withdraw any money from the account any m

olga nikolaevna [1]

Answer: $537.5

Step-by-step explanation:

$500 at 1.5% for 5 years

p x r x t = i

500 x 0.015 x 5= 37.5

37.5+500=537.5

7 0

3 years ago

Choose the values of the range given the function below. {(-1, -3), (5,7). (8. -4), (-7, 3), (-5, 11)}

lyudmila [28]

Answer:

the answer is 53454

Step-by-step explanation:

1+1=1

6 0

2 years ago