In simplest radical form, what are the solutions to the quadratic equation 6 = x2 – 10x?
1 answer:
Answer:
Step-by-step explanation:
quadratic equation: ax² + bx + c =0
x' = [-b+√(b²-4ac)]/2a and x" = [-b-√(b²-4ac)]/2a
6 = x² – 10x ; x² - 10x -6 =0
(a=1, b= - 10 and c = - 6
x' = [10+√(10²+4(1)(-6)]/2(1) and x" = [10-√(10²+4(1)(-6)]/2(1)
x' =5+√31 and x' = 5-√31
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The answer would be commutative.
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Photon
Answer:
3 × a × 2 × b = 3a × 2b
Answer:
I think A is the answer
but D is the correct answer "kunno"
Step-by-step explanation:
hope it helps :)
Let the width be x
The length would be 2x-5
So, 2(x+2x-5)=80
3x-5=40
3x=45
x=15.
So the width is 15 and the length would be 25.
