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Readme [11.4K]
3 years ago
12

What is 49 in exponential form

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
5 0
I think you are asking about seven squared
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I'm assuming you didn't mean to repeat each number 3 times. 

If she did 184 jumping jacks in 4 minutes that means she did 46 jumping jacks per minute. 
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Step-by-step explanation:

its 12 yd

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Which algebraic expression is a polynomial? 3m2n-2m/n+1/n
Lesechka [4]

Answer:

d) 7mn+\frac{3m}{2}+\frac{5n}{4}

Step-by-step explanation:

Which algebraic expression is a polynomial?

a)3m^2n-\frac{2m}{n}+\frac{1}{n}  \\b)\frac{2mn}{5}-\frac{\sqrt{m} }{4} +4m^5\\c)\frac{4m^3}{n^2}-3mn^5+\sqrt{8}\\d)7mn+\frac{3m}{2}+\frac{5n}{4}

Answer: A polynomial is an expression with variables and coefficients separated by addition and subtraction. The following are used when determining if an expression is a polynomial:

i) Variables of a polynomial must not have negative exponent.

ii) Variables of a polynomial must not have fractional exponent.

iii) Dividing by an exponent is not allowed

iv) Exponent radicals are not allowed.

a) 3m^2n-\frac{2m}{n}+\frac{1}{n} is not a polynomial because dividing by an exponent is not allowed.

b) \frac{2mn}{5}-\frac{\sqrt{m} }{4} +4m^5, is not a polynomial because exponent radicals are not allowed (√m)

c) \frac{4m^3}{n^2}-3mn^5+\sqrt{8} is not a polynomial because dividing by an exponent is not allowed.

d) 7mn+\frac{3m}{2}+\frac{5n}{4} is a polynomial

4 0
3 years ago
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c)   P(win first game)  = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game)  × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

P(X = 0)  =  P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game)  × P(win second game)] + [ P(win first game)  × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value  \mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66

f) Variance \sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844

Standard deviation \sigma=\sqrt{variance} = \sqrt{0.3844}=0.62

8 0
3 years ago
I need help with algebra function notation
lutik1710 [3]
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