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hoa [83]
3 years ago
14

Let set A = {odd numbers between 0 and 100} and set B = {numbers between 50 and 150 that are evenly divisible by 5}. What is A ∩

B? (2 points)
Mathematics
1 answer:
fgiga [73]3 years ago
6 0
<span>A = {odd numbers between 0 and 100}
</span><span>A = {1, 3, 5, 7,...., 95, 97, 99}

B = </span><span>{numbers between 50 and 150 that are evenly divisible by 5}
B = {50, 55, 60, 65, ..., 140, 145, 150}

The notation </span><span>A ∩ B means the set of items that are in set A and also in set B. In terms of venn diagrams, it's the overlapping region between circle A and circle B

In this case, the following values are found in both set A and set B
{55, 65, 75, 85, 95}

So that's why 
</span>A ∩ B = <span>{55, 65, 75, 85, 95}
which is the final answer
</span>
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A bag contains 15 marbles. The probability of randomly selecting a green marble is One-fifth. The probability of randomly select
dsp73

Given:

Total number of marbles = 15

Probability of randomly selecting a green marble = \dfrac{1}{5}.

Probability of randomly selecting a green marble, replacing it, and then randomly selecting a blue marble = \dfrac{2}{25}.

To find:

The number of blue marbles.

Solution:

Let the number of blue marbles be x.

\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

P(Blue)=\dfrac{x}{15}

It is given that,

P(Green)=\dfrac{1}{5}

Probability of randomly selecting a green marble, replacing it, and then randomly selecting a blue marble is \dfrac{2}{25}. So,

P(Green)\times P(Blue)=\dfrac{2}{25}

\dfrac{1}{5}\times \dfrac{x}{15}=\dfrac{2}{25}

\dfrac{x}{75}=\dfrac{2}{25}

Multiply both sides by 75.

\dfrac{x}{75}\times 75=\dfrac{2}{25}\times 75

x=2\times 3

x=6

Therefore, the number of blue marbles in the bag is 6.

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3 years ago
In the Atlanta metropolitan area, 723 new cases of invasive cancer of the cervix occurred among white women between 1975 and 198
slamgirl [31]

Answer:

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Step-by-step explanation:

Given the following :

Newly recorded cases of invasive cervical cancer = 723

Period of time = 1975 - 1984 ( inclusive)

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Incidence rate = (723/620000) × 10^n

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= 1.166 per 1000 of population

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Step-by-step explanation:

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