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pentagon [3]
3 years ago
8

Oakland has an elevation of 1,639 feet above sea level lake enriquilos elevation is 149 feet below sea level what difference in

altitude beween is difference in the two locations
Mathematics
1 answer:
castortr0y [4]3 years ago
6 0
The answer here is simple, just multiply your to numbers and divide it by two!<span />
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-6(w - 4) + 8W=6(w + 2)​
Nesterboy [21]

Answer:

w = 3

Step-by-step explanation:

-6(w - 4) + 8W=6(w + 2)​

-6w + 24 + 8w = 6w + 12

2w + 24 = 6w + 12

12 = 4w

3 = w

7 0
3 years ago
Read 2 more answers
PLEASE PLEASE PLEASEE PLEASEEEEESE HELPME!?!?!? IM SO BAD AT MATH PLEASE HELP!!!
Fiesta28 [93]
For this case we have the following function:
 f (x) = 0.01 * (2) ^ x&#10;
 By definition, the average rate of change is given by:
 AVR =  \frac{f(x2) - f(x1)}{x2 - x1}
 We evaluate the function for the given values:
 For x = 7:
 f (7) = 0.01 * (2) ^ 7&#10;&#10;f (7) = 1.28
 For x = 14:
 f (14) = 0.01 * (2) ^ {14}  f (14) = 163.84
 Then, replacing values we have:
 AVR = \frac{163.84 - 1.28}{14 - 7}
 AVR = 23.22
 Answer:
 
the average rate of change from x = 7 to x = 14 is:
 
a. 23.22 
7 0
4 years ago
How many solutions?
Sunny_sXe [5.5K]

Answer: C

Step-by-step explanation: all real numbers can solve this problem

5 0
3 years ago
Read 2 more answers
For the following problem, assume that all given angles are in simplest form, so that if A is in QIV you may assume that 270° &l
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

Given that angle A is in IV quadrant

So A/2 would be in II quadrant.

sin A = -1/3

cos A = \sqrt{1-sin^2 A} =\frac{2\sqrt{2} }{3}

(cos A is positive since in IV quadrant)

Using this we can find cos A/2

cosA = 2cos^2 \frac{A}{2} -1\\Or cos \frac{A}{2} =-\sqrt{\frac{1+cosA}{2} } =-\sqrt{\frac{3+2\sqrt{2} }{6} }

3 0
3 years ago
Giải phương trình y'=0 biết:y=x^4
Mila [183]

Answer:

0.

Step-by-step explanation:

1) y'=(x⁴)'=4x³;

2) ∡ y'=0, ⇒ 4x³=0; ⇒ x=0.

7 0
3 years ago
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