The tires are similar in shape. This means that if they undergo the same number of revolutions, the ratio of the distances covered would be equal to the ratio of the radius of each tire.
From the information given,
radius of tire 1 = 9
distance covered by tire 1 = 8482
let radius of tire 2 = r
distance covered by tire 2 = 5654
Thus,
8482/5654 = 9/r
By crossmultiplying, we have
r * 8482 = 5654 * 9
8482r = 50886
r = 50886/8482
r = 5.9993
By rounding to the nearest whole number,
radius of second tire = 6 inches
Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
For number 7, x is smaller than 9, for number 8, x is bigger than 8.
Just February...but each four years this month has 29 days.
The answer to your question is C because it makes sense