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3 years ago

For what values of n is the perimeter of square A less than the perimeter of rectangle B?

Mathematics

1 answer:

solong [7]3 years ago

5 0

Answer:A

Step-by-step explanation:

I just took the test

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Free think fast 20X10

Kryger [21]

20x10=200 Regards To you

7 0

3 years ago

Read 2 more answers

The measure of the angle is

slavikrds [6]

Answer:

x=8

Step-by-step explanation:

4x+7=6x-9

subtract 4x to 6x

7=2x-9

add 9 to 7

16=2x

divide 2 to 16

x=8

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8 0

3 years ago

1) Eliot and William went hiking. They went at the same speed. Eliot's hike was 8 miles, and William's hike was 12 miles. It too

Vitek1552 [10]

Answer:

1) 2 hours

2) 96 miles

Step-by-step explanation:

1) Eliot and William went hiking. They went at the same speed. Let x mph be their speed.

Elliot:

Distance = 8 miles

Speed = x mph

Time $=\dfrac{8}{x}$ hours

William:

Distance = 12 miles

Speed = x mph

Time $=\dfrac{12}{x}$ hours

It took Eliot $40\ min=\dfrac{40}{60}\ hour=\dfrac{2}{3}\ hour$ less than William, then

$\dfrac{8}{x}+\dfrac{2}{3}=\dfrac{12}{x}\\ \\\dfrac{2}{3}=\dfrac{12}{x}-\dfrac{8}{x}\\ \\\dfrac{2}{3}=\dfrac{4}{x}\\ \\2x=3\cdot 4\ \ [\text{Cross multiply}]\\ \\2x=12\\ \\x=6\ mph$

So, William's hike was

$\dfrac{12}{6}=2$

hours long.

2) Initially:

Distance = 120 miles

Speed = 55 mph

Time $=\dfrac{120}{55}=2\dfrac{10}{55}=2\dfrac{2}{11}\$ hours

Final:

Speed = 44 mph

Time $=2\dfrac{2}{11}$ hours

Distance $=44\cdot 2\dfrac{2}{11}=44\cdot \dfrac{24}{11}=4\cdot 24=96\ miles$

8 0

3 years ago

What is the area of the shaded portion of the figure above

Lemur [1.5K]

Answer:

i need help too

Step-by-step explanation:

plese

8 0

3 years ago

A triangle is dilated with the center of dilation at point U. Point E is a vertex of the triangle and point E ′ E' is the corres

Snezhnost [94]

Answer: $scale\ factor=5$

Step-by-step explanation:

By definition, a Dilation is a transformation in which the image has the same shape as the pre-image but size changes.

The center of dilation is a fixed point in the plane, and the scale factor is the ratio of the corresponding sides of the image to the pre-image.

Based on the information provided in the exercise, you know that:

$UE = 2\ cm\\\\U'E'=10\ cm$

Thererefore, you can determine that the scale factor is:

$scale\ factor=\frac{10\ cm}{2\ cm}\\\\scale\ factor=5$

4 0

4 years ago