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3 years ago

Divide and write your answer in simplest form.5/ 6÷8

Mathematics

1 answer:

Stels [109]3 years ago

4 0

5/6 ÷ 8
= 5/6 x 1/8
= 5/48

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3 years ago

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mario62 [17]

The baskets that DO have eggs in the baskets are 2 3 4 26 34 46
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3 years ago

Read 2 more answers

Rewrite 1 3/4 using twentieths

Evgesh-ka [11]

The correct answer is 29/20

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2 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago

Of the 52 cards in the deck, four are aces and others (kings, queens, jacks, and tens) are worth 10 points each. The dealer has

VLD [36.1K]

Answer:

64 different black jack hands

Step-by-step explanation:

there are 4 aces in a deck, and you can score a blackjack if any of these 4 aces is paired with any of the 16 different cards that are worth 10 points. Total number of different blackjack combinations = 4 aces x 16 different tens = 64.

Even though the number of possible blackjack hands might seem large, the possibilities of actually getting one are really low:

possibility of getting 1 ace = 4/52 = 1/13

possibility of getting 1 ten = 16/51

possibility of getting a blackjack = 16 / 663

if you start with the 10 first the odds are the same:

possibility of getting 1 ten = 16/52 = 4/13

possibility of getting 1 ace = 4/51

possibility of getting a blackjack = 16 / 663

5 0

3 years ago