An actual Canadian quarter has a diameter of 23.88 mm. Calculate the scale factor used to create the

angelo's mother put $50 on a lunch card he spends the same amount each day for lunch. what is the constant rate of change for th

Rina8888 [55]

Given that Angelo spends the same amount everyday from the amount in

the lunch card, the function of the amount remaining is a linear function.

The constant rate of change of the function is; -5.25

The two ordered pair used to find the constant rate of change are; (1, 44.75) and (2, 39.5)

Reasons:

The amount Angelo's mother put on the lunch card = $50

A possible table of values to the question is presented as follows;

$\begin{tabular}{r|c|c|c|c|}Days&0&1&2&3\\Money Remaining&&44.75&39.5&\end{array}\right]$

Required:

The constant rate of the function that gives the amount remaining from the

amount Angelo's mother put on his lunch card.

Solution:

$Slope \ or \ constant \ rate \ of \ change = \mathbf{\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}$

The two ordered pair that can be used to find the slope or constant rate of change are;

(x₁, y₁) = (1, 44.75), and (x₂, y₂) = (2, 39.5)

With the above two ordered pairs, we have the constant rate of change of the function given as follows;

$Constant \ rate \ of \ change\ (The \ slope) =\dfrac{39.5-44.75}{2-1} = \mathbf{ -5.25}$

The constant rate of change for the function that gives the amount remaining in the lunch card is; -5.25

Learn more about the constant rate of change of a function here:

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3 0

2 years ago

Andrew

PilotLPTM [1.2K]

Let's say Bailey takes "b" days to paint it.

and Andrew takes "a" days to paint the same house.

now, Andrew is 6 times faster than Bailey, therefore, if Andrew takes "a" days to do it, Bailey takes then "6a" days, or b = 6a.

now, the year they worked together, they finished it in 7 days.

so, after 1 day then, they have only done 1/7 of the whole work.

and Andrew for one day, has done 1/a of the house, whilst Bailey has done 1/b of the house or 1/(6a).

$\bf \stackrel{\textit{Andrew's rate}}{\cfrac{1}{a}}+\stackrel{\textit{Bailey's rate}}{\cfrac{1}{b}}=\stackrel{\textit{1 day of work}}{\cfrac{1}{7}}
\\\\\\
\cfrac{1}{a}+\cfrac{1}{6a}=\cfrac{1}{7}\impliedby 
\begin{array}{llll}
\textit{let's multiply all by }\stackrel{LCD}{42a}\textit{ to toss the}\\
denominators
\end{array}$

$\bf 42a\left( \cfrac{1}{a}+\cfrac{1}{6a} \right)=42a\left( \cfrac{1}{7} \right)\implies 42+7=6a\implies \cfrac{49}{6}=a
\\\\\\
\stackrel{days}{8\frac{1}{6}}=a
\\\\\\
\textit{how many days will it take Bailey then?}\quad b=6a
\\\\\\
b=6\cdot \cfrac{49}{6}\implies b=\stackrel{days}{49}$

6 0

3 years ago

Find the equation of a line parallel to line y=6 that passes through the point (-2,-1)

ohaa [14]

Answer:

y=-1

Step-by-step explanation:

yeah-ya...... right?

4 0

2 years ago

Amy received a $80 gift card for a coffee store. She used it in buying some coffee that cost $8.24 per pound. After buying the c

SVEN [57.7K]

Answer:

5 pounds

Step-by-step explanation:

Given that:

Amount of gift card = $80

Cost of coffee per pound = $8.24

Amount left in the card = $38.80

To find:

Number of pounds of coffee bought = ?

Solution:

Let the number of pounds of the coffee bought = $x$ pounds

Cost of 1 pound = $8.24

Cost of $x$ pounds = $8.24 $\times x$

Writing the equation as per question statement:

$80 - 8.24x = 38.80\\\Rightarrow 80 - 38.80 = 8.24x\\\Rightarrow 8.24x = 41.2\\\Rightarrow x = \dfrac{41.2}{8.24}\\\Rightarrow \bold{x = 5\ pounds}$

Therefore, 5 pounds of coffee was bought.

3 0

3 years ago

How do you subtract integers? like -81-(-34)

DedPeter [7]

Answer:

-47

Step-by-step explanation:

For this problem, we can use the rule "two negatives make a positive".

-81-(-34)

= -81 + 34

If you subtract 34 from 81, you find the opposite positive/negative answer.

81 - 34 = 47

Change all of the positive/negative signs:

-81 + 34 = -47

8 0

3 years ago