Step-by-step explanation:
Mark each mark by 15 mins add an extra tick at the time section
the corner before the first 15 min mark make a tilted line to 15 mins and 30,000 feet draw a straight line till 2 hours and 15 mins draw titled down to 2 hours and 30 mins
Answer:
D
Step-by-step explanation:
Change the x and y
Then solve for y
X= 8y+1
Subtract 1 from both sides
X-1=8y
Divide by 8
X-1 /8 = y
Answer:
y = - 2x + 6
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = 
with (x₁, y₁ ) = (1, 4 ) and (x₂, y₂ ) = (2, 2 )
m =
=
= - 2 , then
y = - 2x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (2, 2 ) , then
2 = - 4 + c ⇒ c = 2 + 4 = 6
y = - 2x + 6 ← equation of line
The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>