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Digiron [165]
4 years ago
12

A circle with a radius of 3cm sits inside a 8cm*7cm rectangle. What is the area of the shaded region? Round your final answer to

the nearest hundredth.

Mathematics
2 answers:
Elanso [62]4 years ago
7 0

Answer:

27.73 cm squared

Step-by-step explanation:

In order to find the shaded region, we need to find the areas of the circle and the rectangle and then subtract the circle area from the rectangle area.

The area of a rectangle is denoted by: A = lw, where l is the length and w is the width. Here, the length is l = 7 and the width is w = 8. Plug these in:

A = lw

A = 7 * 8 = 56 cm squared

The area of a circle is denoted by: A = πr², where r is the radius. Here, the radius is r = 3, so plug this in:

A = πr²

A = π * 3² = 9π ≈ 28.27 cm squared

Now subtract 28.27 from 56:

56 - 28.27 = 27.73

The answer is thus 27.73 cm squared.

timurjin [86]4 years ago
5 0

Answer:

27.73 cm squared

Step-by-step explanation:

The area of a circle is denoted by: A = πr², where r is the radius. Here, the radius is r = 3, so plug this in:

A = πr²

A = π * 3² = 9π ≈ 28.27 cm squared

Now subtract 28.27 from 56:

56 - 28.27 = 27.73

The answer is thus 27.73 cm squared.

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Mario fille a hummingbird feeder with 3/4 cup of sugar water on Friday .Monday , Mario sees that 1/8 of sugar water is left .how
tino4ka555 [31]

\frac{5}{8} of total sugar was drink by humming bird

<h3><u>Solution:</u></h3>

Given that,

When the Mario kept the humming feeder on Friday it had \frac{3}{4} cup of sugar water

When he sees on Monday, it had only \frac{1}{8} of sugar water

So, this means the water is consumed by the humming bird will be the difference of the two values:-

\text { Sugar water consumed }=\frac{3}{4}-\frac{1}{8}

On solving we get,

=\frac{3}{4}-\frac{1}{8}=\frac{24-4}{32}=\frac{20}{32}

=\frac{5}{8}

Hence, the amount of sugar water consumed is \frac{5}{8} of total sugar at the starting

5 0
4 years ago
2(x+7)+3(x+1) what is the answer
barxatty [35]

Answer:

5x + 17

Step-by-step explanation:

To answer this question, we must first simplify:

2 (x + 7) + 3 (x + 1) = 2x + 14 + 3x + 3

Then, we have to combine like terms:

2x + 14 + 3x + 3 = 5x + 17

And there is our answer, 5x + 17

Hope this helps ! :)

5 0
4 years ago
What is the second step when evaluating the expression 49 + 63 ÷ (3 + 2 × 2) – 7? 63 ÷ 3 63 ÷ 7 2 × 2 3 + 4
Zarrin [17]

ANSWER: Multiply and Divide from left to right

To do this question we must follow the rules of PEMDAS. The first step would be to evaluate the equation given to us in the parentheses. To solve that we would have to use PEMDAS once again which tells us to multiply 2 x 2 before we add 3, so we get 7. Now that there is no more Parentheses, our second step is to evaluate each Multiplication and Division expression from left to right. This would start by dividing 63 by 7 to get 9.

7 0
3 years ago
What are all examples of rational numbers?
tresset_1 [31]

Answer:

1/7, 2, 0.62, 40000000002342, 13, 23/478

Step-by-step explanation:

A number is rational if we can write it as a fraction, where both denominator and numerator are integers and denominator is a non-zero number.

6 0
3 years ago
i already have the answers but i need to show my work. ill tell you my insta and please show me a picture of the work :))
Elodia [21]

Answer:

1:

{( - 6)}^{2}  \times  {( - 6)}^{5}

from law of indices:

{a}^{n}  \times  {a}^{m}  =  {a}^{(n + m)}

therefore:

= ( - 6) {}^{ \{2 + 5 \}}  \\  = ( - 6) {}^{7}  \\  = { \boxed{ \boxed{ - 279936}}}

2:

- 4 {a}^{5} (6 {a}^{5} ) \\  = ( - 4 \times 6)( {a}^{5}  \times  {a}^{5} ) \\  =  - 24  \{{a}^{(5 + 5)}  \} \\  = { \boxed{ \boxed{ - 24 {a}^{10} }}}

3:

( - 7 {a}^{4} b {c}^{3} )(5a {b}^{4}  {c}^{2} ) \\  = ( - 7 \times 5)( {a}^{4}  \times a)(b \times  {b}^{4})  \times ( {c}^{3}  \times  {c}^{2} ) \\  =  - 35 {a}^{5}  {b}^{5 }  {c}^{5}  \\  = { \boxed{ \boxed{ - 35 {(abc)}^{5} }}}

4:

\frac{ {8}^{15} }{ {8}^{13} }

from law of indices:

\frac{a {}^{n} }{ {a}^{m} }  =  {a}^{(n - m) }  \\

therefore:

=  {8}^{(15 - 13)} \\ { \boxed{ \boxed{ {8}^{2} = 64 }}}

follow the procedure for application to other questions.

<em>Any</em><em> </em><em>question</em><em>,</em><em> </em><em>be</em><em> </em><em>free</em><em> </em><em>to</em><em> </em><em>ask</em><em>.</em><em> </em>Thank you …

6 0
3 years ago
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