Answer:
![\sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%5E%7B2%7D%2Bb%5E%7B2%7D%7D%3D%28a%5E%7B2%7D%2Bb%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
Step-by-step explanation:
∵∛x = (x)^1/3
∴
So you can replace the radicals by fractional exponents
We will set each parentheses equal to 0
x - 4 = 0
x = 4
-5x + 1 = 0
x = 1/5
The lesser value will be 1/5
The greater value will be 4
If it snows do I have to do my homework
Answer:
the answer is going to be 496,000. If you meant "Thousandth" and not "Thousand" the answer is going to be 496,179.784
Answer:
no solution
Step-by-step explanation:
12x − 18y = 27
4x − 6y = 10
Multiply the second equation by -3 so we can eliminate x
-3(4x − 6y) = 10*-3
-12x +18y = -30
Add the first equation to this new equation
12x − 18y = 27
-12x +18y = -30
------------------------
0 = -3
This is not a true equation, so there is no solution
