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Volgvan
3 years ago
10

In the accompanying figure. ABCD is a square. LaTeX: AB=5x-10 A B = 5 x − 10 and LaTeX: BC=2x+20. B C = 2 x + 20. Find the value

of x.
Mathematics
1 answer:
jek_recluse [69]3 years ago
8 0
Answer:
x = 10

Explanation:
A square is a quadrilateral in which all sides are equal.

We are given that:
ABCD is a square
AB = 5x - 10
BC = 2x + 20

Since we're talking about a square, therefore:
AB = BC
5x - 10 = 2x + 20
5x - 2x = 20 + 10
3x = 30
x = 30/3
x = 10

Now, we can check our solution:
AB = 5(10) - 10 = 40 units
BC = 2(10) + 20 = 40 units
We can see that both sides are equal

Hope this helps :)
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To solve this you want to plug in your x's and y's to see if they match.

A. 3(11)-4=33-4=29 and 29 is not equal to 5 so A is not a solution

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What are the roots of the polynomial equation x^3-5x+5=2x^2-5? Use a graphing calculator and a system of equations. Round nonint
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The right answer is c. –2.24, 2, 2.24


This question needs to be solved in two ways. First, using a graphing calculator. Next, using a system of equations.


1. Using a graphing calculator.


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x^3-5x+5=2x^2-5


By ordering this equation we have:

x^3-2x^2-5x+10=0


So, we can say that this equation comes from a function given by:

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Finally, rounding noninteger roots to the nearest hundredth we have:


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