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Leni [432]
3 years ago
8

Sofia is learning to knit. After her first three stitches, she had to undo the last two. Then she made three more stitches and a

gain, had to undo the last two. If this pattern continues, how many stitches will Sofia have to make before she has six good stitches?
Mathematics
2 answers:
STALIN [3.7K]3 years ago
5 0
I think so 3 times because the first time the total was 2
2*3 is 6
Roman55 [17]3 years ago
4 0
18 stitches I think I don't know use Google. that will help
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Yeah thats right y u pretty much asked a true or false question 
8 0
4 years ago
If the inequality has < or >, then your graph will have what type of line
victus00 [196]

If the inequality has < or >, then your graph will have a linear inequality. This is still a line and a half-plane.

Answer: Linear inequality

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3 0
3 years ago
Harold uses the binomial theorem to expand the binomial (3x^5 - 1/9y^3)^4
riadik2000 [5.3K]
<h3><em>The complete question:</em></h3>

<u><em> </em></u><u>Harold uses the binomial theorem to expand the binomial </u>(3x^5 -\dfrac{1}{9}y^3)^4<u />

<u>(a)    What is the sum in summation notation that he uses to express the expansion? </u>

<u>(b)    Write the simplified terms of the expansion.</u>

Answer:

(a). (3x^5 -\dfrac{1}{9}y^3)^4=$$\sum_{k=0}^{n}  \binom{4}{k}(3x^5)^{4-k}( -\dfrac{1}{9}y^3)^k $$

(b).(3x^5 -\dfrac{1}{9}y^3)^4=81x^{20}-12x^{15}y^3+\dfrac{2x^{10}y^6}{3}-\dfrac{4x^5y^9}{243}+\frac{y^{12}}{6561}

Step-by-step explanation:

(a).

The binomial theorem says

(x+y)^n=$$\sum_{k=0}^{n}  \binom{n}{k}x^{n-k}y^k $$

For our binomial this gives

\boxed{(3x^5 -\dfrac{1}{9}y^3)^4=$$\sum_{k=0}^{n}  \binom{4}{k}x^{4-k}y^k $$}

(b).

We simplify the terms of the expansion and get:

$$\sum_{k=0}^{n}  \binom{4}{k}(3x^5)^{4-k}y^k $$= \binom{4}{0}(3x^5)^{4-0}(-\dfrac{1}{9}y^3 )^0+\binom{4}{1}(3x^5)^{4-1}(-\dfrac{1}{9}y^3 )^1+\\\\\binom{4}{2}(3x^5)^{4-2}(-\dfrac{1}{9}y^3 )^2+\binom{4}{3}(3x^5)^{4-3}(-\dfrac{1}{9}y^3 )^3+\binom{4}{4}(3x^5)^{4-4}(-\dfrac{1}{9}y^3 )^4

$$\sum_{k=0}^{n}  \binom{4}{k}(3x^5)^{4-k}(-\frac{1}{9}y^3 )^k $$= (3x^5)^{4}+4(3x^5)^{3}(-\frac{1}{9}y^3 )+6(3x^5)^{2}(-\frac{1}{9}y^3 )^2+\\\\4(3x^5)(-\frac{1}{9}y^3 )^3+(-\frac{1}{9}y^3 )^4

\boxed{(3x^5 -\dfrac{1}{9}y^3)^4=81x^{20}-12x^{15}y^3+\dfrac{2x^{10}y^6}{3}-\dfrac{4x^5y^9}{243}+\frac{y^{12}}{6561}   }

3 0
3 years ago
Line A passes through the coordinate points (-2/5,0) and (0,1). Which of the following lines will line A never intersect? ​
expeople1 [14]

Answer:

Option B

Step-by-step explanation:

Only lines which are parallel to the line which connects the given two points will neve r intersect,

parallel line has same slope

the slope of the line which connects the given two points is, 5/2

and the line is option B also has the same slope, so those two lines will never intersect each other.

Answered by GAUTHMATH

4 0
3 years ago
At a store, bananas cost $0.68 per pound. How much will 4 1/2 pounds of bananas cost?
yulyashka [42]

Answer:

$3.06

Step-by-step explanation:

Based on the question that was given, we can see that for every *one* pound,  the cost of the bananas is $0.68.

Since we are looking for how much 4 1/2 pounds is worth, we can convert this to 4.5 and simply multiply $0.68 by 4.5, giving us a grand total of $3.06

6 0
3 years ago
Read 2 more answers
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