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3 years ago

If f(x) = x^3-3, what is the average rate of change of f(x) over the interval [-4, 6]f?

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

7 0

Answer

42 would be the answer

Step-by-step explanation:

Vinil7 [7]3 years ago

6 0

42 is the answer your looking for.

You might be interested in

Find B on AC that is 2/5 of the distance of A to C.

salantis [7]

Answer:

Step-by-step explanation:

AC = 5, ao AB = 2.

This means B = -1+2 = 1.

3 0

1 year ago

Please answer this!!!!!!!

aivan3 [116]

Answer:

-4

Step-by-step explanation:

Rewrite 16 as 4 squared

Pull terms out from under the radical, assuming positive real numbers

-1 x 4

Then you get the answer -4

4 0

3 years ago

Pls help!!!!The probability of hitting a target on a single trial is 40%,Find the probability of hitting the same target 5/8 tim

azamat

Probability hit=40%=4/10
probability no hit=1-p (hit)=1-4/10=6/10
probability= p(hit)+p(hit)+p(hit)+p(hit)+p(hit)+p (no hit)+p (no hit)+p (no hit)
probability=4/10×4/10×4/10×4/10×4/10×6/10×6/10×6/10
=0.0022
( I think but I'm not 100% sure)

6 0

2 years ago

Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.

lakkis [162]

Answer:

$2*sin(x)+y*cos(x)-cos(y)=C_1$

Step-by-step explanation:

Let:

$P(x,y)=2*cos(x)-y*sin(x)$

$Q(x,y)=cos(x)+sin(y)$

This is an exact differential equation because:

$\frac{\partial P(x,y)}{\partial y} =-sin(x)$

$\frac{\partial Q(x,y)}{\partial x}=-sin(x)$

With this in mind let's define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x}=P(x,y)$

and

$\frac{\partial f(x,y)}{\partial y}=Q(x,y)$

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y)

$f(x,y)=\int\ 2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)$

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}$

Now, let's replace the previous result into $\frac{\partial f(x,y)}{\partial y}=Q(x,y)$ :

$cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)$

Solving for $\frac{dg(y)}{dy}$

$\frac{dg(y)}{dy}=sin(y)$

Integrating both sides with respect to y:

$g(y)=\int\ sin(y) \, dy =-cos(y)$

Replacing this result into f(x,y)

$f(x,y)=2*sin(x)+y*cos(x)-cos(y)$

Finally the solution is f(x,y)=C1 :

$2*sin(x)+y*cos(x)-cos(y)=C_1$

7 0

3 years ago

What is the area of the triangle in centimeters<br> squared?

Rashid [163]

Answer:

A = 112cm²

Step-by-step explanation:

Area of a triangle = (bh) / 2

b = base length and h = height

The triangle shown has a given base length of 14cm and a given height of 16cm

Hence area = ( 16 * 14 ) / 2

16 * 14 = 224

224 / 2 = 112

A = 112cm²

7 0

2 years ago