If we are to derive the equation that models the growth of the amoeba, we make use of the general form:
p = po k^t
where po is the initial population
k is the multiplicative rate of change
From the problem
3po = po k^(20)
k = 1.06
The equation is
p = 800 (1.06)^t
So 9x<18 can be factored out into
9(x)<9(2)
you can divide both sides by 9
x<2
so the solution is any number more than 2, but not 2
Answer:
9 groups with 6 extra students
Step-by-step explanation:
78/8= 9 .75
we take the whole number =9
8*9=72
78-72=6
6 extra students
