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sammy [17]
4 years ago
11

Steve and his daughter went on 30- mile backpacking trek in Yosemite national park. They hiked 7.7 mi the first day , 6.4 the se

cond day and 8.0 mi the third day. How much farther did they have to go ?
Mathematics
1 answer:
Liula [17]4 years ago
7 0

To answer this question you basically have to add up day 1, day 2 and day three then take it away from 30 so.....

7.7+6.4+8.0=22.1

30-22.1=7.9 so they have 7.9 miles left to walk

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To solve this problem you must apply the proccedure shown below:

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