Answer:
$27
Step-by-step explanation:
0.3 x 90 = $27
30% of your money is $27, so the football must've cost $27.
Answer:
11.1 units
Step-by-step explanation:
We solve for this using the formula when using coordinates (x1 , y1) and (x2, y2)
= √(x2 - x1)² + (y2 - y1)²
A(5,2), B(5,4), and C(1,1).
For AB = √(x2 - x1)² + (y2 - y1)²
= A(5,2), B(5,4)
= √(5 - 5)² +(4 - 2)²
= √ 0² + 2²
= √4
= 2 units
For BC = √(x2 - x1)² + (y2 - y1)²
= B(5,4), C(1,1)
= √(1 - 5)² +(1 - 4)²
= √ -4² + -3²
= √16 + 9
= √25
= 5 units
For AC = √(x2 - x1)² + (y2 - y1)²
A(5,2), C(1,1)
= √(1 - 5)² + (1 - 2)²
= √-4² + -1²
= √16 + 1
= √17
= 4.1231056256 units
The Formula for the Perimeter of Triangle = Side AB + Side BC + Side AC
= 2 units + 5 units + 4.1231056256 units
= 11.1231056256 units.
Approximately the Perimeter of a Triangle to the nearest tenth = 11.1units
Answer:
The maximum amount of money the chemistry club can spend without going over their buget is $81.4 ... With a total of 6 hours their allowed to use the room for.
Step-by-step explanation:
$49 is our constant and will not change. 5.40 however will. Let's use variable h for the amount hours they can rent the room for. Now we can make an inequality;
49+ 5.40h < 86.80
5.40h < 86.80
5.4h< 37.8
h< 7
Now that we know h will have to be less than seven for the chemistry club to spend less than their buget we can find that 6 is the maxium amount of hours they can spend in the room while staying within their budget.
(This answer does not consider decimals or half hours)
Answer:
6000 in³
Step-by-step explanation:
To solve this problem, we simply have to find the volume of the shipping container that will be just enough to contain the 20 soda boxes.
To do this, we find the volume of each soda box and multiply it by the total number of soda boxes held by the shipping container.
Volume of the box = L * B * H
L = length = 15 in
B = breadth = 4 in
H = height = 5 in
V = 15 * 4 * 5 = 300 in³
This is the volume of each soda box.
The volume of 20 soda boxes will then be:
V = 20 * 300 = 6000 in³
This is the volume of 20 soda boxes and hence, the minimum size the shipping container can be.
I think your answer is B. -1/2
Explanation: the rise is -4 and the run is 8. If u divide those by 2, you get -2 and 4. You divide that by half and get -1/2??
