All categories

3 years ago

What is the MAD of the data set (10,9,16,5,10

1 answer:

6 0

I just don’t know what I was doing but it wasn’t so hard I gotta love y’all and ya welcome to my boyfriend I love y’all ya know y’all don’t know

You might be interested in

In Illinois, 10 % of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders; that is, they have been ar

docker41 [41]

Answer:

a) P(X=5) = 0.065

b) P(X≥1) = 0.928

c) The mean number of repeat offenders is 3.

d) The standard deviation of the number of repeat offenders is 2.

Step-by-step explanation:

n = 25

p = 10% = 0.10

q = 1-p

= 1-0.1

q=0.9

a) Find P(X =5)

Using the binomial distribution formula:

P(X = x) = ⁿCˣ pˣ qⁿ⁻ˣ

where p = probability of success

q = probability of failure

n = total number of trials

x = no. of successful trials

P(X=5) = ²⁵C₅ (0.1)⁵ (0.9)²⁵⁻⁵

= 0.0645 ≅ 0.065

P(X=5) = 0.065

b) We need to find the probability that at least one person is a repeat offender which means at most there can be 25 repeat offenders hence, we need to compute the probability for all values ranging from 1 to 25. The easy way to solve this problem is to find out the probability of less than one repeat offender and then subtract the value from the total probability (i.e. 1).

P(X≥1) = 1 - P(X<1)

= 1 - P(X =0)

= 1 - ²⁵C₀ (0.1)⁰ (0.9)²⁵⁻⁰

= 1 - 0.072

P(X≥1) = 0.928

c) The mean of the binomial distribution is:

μ = np

So, the mean number of repeat offenders can be computed as:

μ = (25)(0.10)

μ = 2.5 ≅ 3

The mean number of repeat offenders is 3.

d) The standard deviation of the binomial distribution is:

σ = √npq

So, the standard deviation of the number of repeat offenders can be computed as:

σ = √(25)(0.1)(0.9)

= √2.25

σ = 1.5 ≅ 2

The standard deviation of the number of repeat offenders is 2.

7 0

3 years ago

The Future Government Club wants to sponsor a panel discussion on the upcoming national election. The club wants four of its mem

ella [17]

Simple random selection involves a selection where all the elements in the dataset have the same chance of being selected.

The selected names are:

Engler, Motola, Redmond and Zenkel

We have:

$n =32$ --- All names

$r = 4$ ---- Sample to select

There are several ways to select a sample of 4 using a simple random sample. Some ways are:

Select any 4
List all names in even position and select the first 4
List all names in position divide by 4 and select any 4 that is divided by 8
List all names in odd position and select the first 4 that can be divided by 3
Etc

Going by the third method, the selected positions are:

4, 8, 12, 16, 20, 24, 28 and 32

Select 4 positions that can be divided by 8

8, 16, 24 and 32

So, the selected names are:

Engler, Motola, Redmond and Zenkel

Read more about random selection at:

brainly.com/question/20692763

4 0

3 years ago

Given that f(x)=x^2-3x+3 and g(x)=x-1/4 slove for f(g(x)) when x=5

Y_Kistochka [10]

When x=5, f(g(x)) would be (x-1/4)^2 - 3(x-1/4) + 3 which when you plug 5 in for x, you get 11.3125 as an answer

6 0

3 years ago

Which number is not in the solution set of x-6>10?

givi [52]

Answer:

options?

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

True False Problem Enter T or F depending on whether the statement is true or false. (You must enter T or FTrue and False will n

slamgirl [31]

Answer:

Step-by-step explanation:

5 0

3 years ago