Answer:
years 1–4: 62.4 bass per year
years 5–8: 67.6 bass per year
Step-by-step explanation:
If the population in year n is ...
p(n) = 3000·1.02^n
then the average rate of change from year 1 to year 4 is ...
(p(4) -p(1))/(4 -1) = 3000(1.02^4 -1.02^1)/3 = 1020·(1.02^3 -1) ≈ 62.4
The average rate of change for years 1–4 is 62.4 bass per year.
For years 5–8, the rate of change is similarly computed:
(p(8) -p(5))/(8 -5) = 3000(1.02^8 -1.02^5)/3 = 1000·1.02^5·(1.02^3 -1) ≈ 67.6
The average rate of change for years 5–8 is 67.6 bass per year.
Answer:
y=2x-5
Step-by-step explanation:
i took algebra
Answer:
63
Step-by-step explanation:
the answer is 63 because 6 to the power of 2 is 36 and 3 to the power of 3 is 27 add them together you get 63
The last option is the correct option.
You basically just have to solve for e.
so multiply each side by 4 first.
that makes it 3e < 96
to get e by itself divide each side by 3.
which you e < 32
Step-by-step explanation:
the correct answer is option B
