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Yuki888 [10]
3 years ago
15

Eliminate the parameter.. . x = 7t, y = t + 4

Mathematics
2 answers:
hichkok12 [17]3 years ago
8 0

y=x^7+4 is your answer

GarryVolchara [31]3 years ago
5 0

To answer the given problem, after removing the parameter, you should be able to get  y=<span>x7</span>+4. I am hoping that this answer has satisfied your query and it will be able to help you, and if you would like, feel free to ask another question.

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Tan(x)= 3/2 <br> Find X <br> Plz help
Novosadov [1.4K]
56.30

With a calculator, press second or shift and then tan to find the degrees.

7 0
4 years ago
Simplify. Your answer should contain only positive exponents.<br> 2*2^-3
jonny [76]
0.25 or 1/4 as 2^-3 is 1/8 so 2*1/8 = 2/8 = 1/4
5 0
3 years ago
The sum of two positive integers, a and b is at least 30. The difference of the two integers is at least 10. fb is the greater
Fed [463]

Answer:

a + b \geq  30

b - a \geq  10

Step-by-step explanation:

Given

Two integers a and b

The first statement in the question says, their sum is at least 30

The keyword "at least" means their sum can not fall below 30 and this is represented mathematically as

a + b \geq  30

The next statement says their difference is at least 10 and b is greater;

The keyword "at least" means the same as used above (i.e. can not exceed); The second statement is represented as:

b - a \geq  10

Hence, the system of inequality that represents the statements are:

a + b \geq  30

b - a \geq  10

7 0
3 years ago
A school choir has 36 members. There are three times as many underclass men as seniors. How many seniors are in the choir ?
Ostrovityanka [42]

Answer:

12

Step-by-step explanation:

3x=36

x=12

5 0
3 years ago
Read 2 more answers
How do you do this problem?
icang [17]

Step One

Put the right side over a common denominator.


\dfrac{a(x+ 1)}{*(x + 1)} - \dfrac{bx}{x(x + 1)} =  \dfrac{ax+a - bx}{x(x + 1)} = \dfrac{ax - bx + a}{x(x + 1)}


Step Two

Remove the brackets on the numerator in the last equality.


Step three.

This will seem kind of odd but take out the common factor (x) in the first two terms of the numerator.

\dfrac{x(a - b) + a}{x(x + 1)}


Step Four

What you do next comes up very frequently in your second or third calculus course.


You have to notice that there are no xs in the numerators on the left side of the original expression


Therefore you have to make a - b = 0 so that the xs disappear on the right.

a - b =0

a = b


Step Five

Find a

a is all by itself on the numerator of the final result.

The original question has a 1 in the numerator. Therefore a = 1


Step Six

Solve for b

a = b

1 = b Answer



7 0
3 years ago
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