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Ahat [919]
4 years ago
15

The sum of two numbers is fifteen. The product of the two numbers is thirty six. Find the numbers

Mathematics
2 answers:
quester [9]4 years ago
7 0
One way is to find the factors of 36
factors are
1,36
2,18
3,12
4,9
6,6
add them
1+36=37
2+18=20
3+12=15 match
4+9=13
6+6=12

the numbesr are 3 and 12
Diano4ka-milaya [45]4 years ago
4 0
Best to take this in two parts. 

1, find the factors of 36:
1 and 36
2 and 18
3 and 12
4 and 9
6 and 6

2, Now, using those, add the factors and see which add up to 15... in this case, that would be 12 and 3!
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B is the midpoint of A . If AB = x+5 and BC =2x-11, find the measure of AB
nignag [31]

If B is the midpoint of AC, then AB = BC.

We have AB = x + 5 and BC = 2x - 11.

Therefore we have the equation:

x + 5 = 2x - 11       <em>subtract 5 from both sides</em>

x = 2x - 16       <em>subtract 2x from both sides</em>

-x = -16      <em>change the signs</em>

x = 16

Put the value of x to the expression x + 5:

AB = 16 + 5 = 21

<h3>Answer: AB = 21</h3>
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aleksandr82 [10.1K]

Answer: answer D

Step-by-step explanation:

i am pretty sure it is D. not 100%, but like 90%. they are both on the outside of the lines, so that is why i know they are exterior. and, they are on opposite sides, so that makes them alternate.

8 0
3 years ago
Perform the indicated operations. x+1/3y+x-2/4y-x=3/6y
Varvara68 [4.7K]
The answer: 
_____________________________________________
x = (⅔)y ;

 y = 3x/2.
_____________________________________________
Given:

x + (⅓)y + x - (2/4)<span>y - x = (3/6)y ;
______________________________________ 
</span>
Take  the:  x + x - x = 1x + 1x - 1x = 2x - 1x = 1x = x ; 

and rewrite:

x + (⅓)y - (2/4)y = (3/6)y ;
_______________________________
 Note that:  (2/4)y = (<span>½)y ; 

        and:   (3/6)y = (</span><span>½)y ;  so;
___________________________
Rewrite as:
____________________________
</span>x + (⅓)y - (½)y = (½)y ;

Add "(½)y" to EACH SIDE of the equation;
_________________________________
    x  +  (⅓)y  -  (½)y  + (½)y = (½)y + (½)y ;

to get:  x +  (⅓)y = y ; 

x = 1y - (⅓)y = (3/3) y - (1/3)y - [ (3-1)/3] y = (⅔)y ; 

So:  x = (<span>⅔)y ;

In terms of "y" ; 

Given:  </span>(⅔)y = x ; Multiply each side of the equation by "3" ; 

3*[(⅔)y] = 3*x ;
 
 to get:  2y = 3x ;

Now, divide EACH SIDE of the equation by "2" ; to isolate "y" on one side of the equation; and to solve for "y" (in terms of "x"):

     2y / 2 = 3x / 2 ;

to get:  

      y = 3x/2 ;
___________________________________

6 0
4 years ago
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Novosadov [1.4K]

Answer:

Um never heard of that one sorry

Step-by-step explanation:

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3 years ago
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