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ra1l [238]
4 years ago
12

What is the solution to the equation -(5-(a+1))=9-(5-(2a-3))?

Mathematics
1 answer:
Wewaii [24]4 years ago
5 0
I know the answer. It B!
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Consider the equation 3x + 90 + 2x = 360 how do we solve this?
Ivahew [28]

Answer:

54

Step-by-step explanation:

First add like terms: 5x+90=360

Then subtract 90 from both sides: 5x=270

Then divide both sides by 5: x=54

6 0
4 years ago
A book store is having a 30 perscent off sale. Diary of the wimpy kid books are now 6.30 dollars each what was the original pric
Diano4ka-milaya [45]
Answer = $8.19

6.30(.30) = 1.89

6.30+1.89= 8.19
7 0
3 years ago
У = -11/4
Amiraneli [1.4K]

Answer:

so your answer will be A!!!!!!!

Step-by-step explanation:

-11/8+(-11/4)

=-11/8-11/4

=-11/8-22/8

-33/8

so this is because x represents (-11/8)+ in the equation -11/8+(-11/4), and y represents +(-11/4) in the same equation.

hope this helps!!!!

3 0
3 years ago
In a random sample of cars driven at low altitudes, of them exceeded a standard of grams of particulate pollution per gallon of
Orlov [11]

Complete question is;

In a random sample of 370 cars driven at low altitudes, 43 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed. In an independent random sample of 80 cars driven at high altitudes, 23 of them exceeded the standard. Can you conclude that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard at an level of significance? Group of answer choices

Answer:

Yes we can conclude that there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard (P-value = 0.00005).

Step-by-step explanation:

This is a hypothesis test for the difference between the proportions.

The claim is that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

Then, the null and alternative hypothesis are:

H0 ; π1 - π2 = 0

H1 ; π1 - π2 < 0

The significance level would be established in 0.01.

The random sample 1 (low altitudes), of size n1 = 370 has a proportion of;

p1 = x1/n1

p1 = 43/370

p1 = 0.116

The random sample 2 (high altitudes), of size n2 = 80 has a proportion of;

p2 = x2/n2

p2 = 23/80

p2 = 0.288

The difference between proportions is pd = (p1-p2);

pd = p1 - p2 = 0.116 - 0.288

pd = -0.171

The pooled proportion, we need to calculate the standard error, is:

p = (x1 + x2)/(n1 + n2)

p = (43 + 23)/(370 + 80)

p = 66/450

p = 0.147

The estimated standard error of the difference between means is computed using the formula:

S_(p1-p2) = √[((p(1 - p)/n1) + ((p(1 - p)/n2)]

1 - p = 1 - 0.147 = 0.853

Thus;

S_(p1-p2) = √[((0.147 × 0.853)/370) + ((0.147 × 0.853)/80)]

S_(p1-p2) = 0.044

Now, we can use the formula for z-statistics as;

z = (pd - (π1 - π2))/S_(p1-p2)

z = (-0.171 - 0)/0.044

z = -3.89

Using z-distribution table, we have the p-value = 0.00005

Since the P-value of (0.00005) is smaller than the significance level (0.01), then the effect is significant.

We conclude that The null hypothesis is rejected.

Thus, there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

6 0
3 years ago
-3 1/5 ÷ 1 3/4<br> Write your answer as a mixed number in simplest form.
Ipatiy [6.2K]
So the answer would be negative 64 over 35
5 0
3 years ago
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