0 is the answer Hope this helps
Answer:
Step-by-step explanation: . y - 7 = -3⁄4 (x +5)
1. y = -3/4(x+5) + 7
2. y = -3/4x + -15/4 + 7
3. y = -3/4x + 13/4
Answer:
Step-by-step explanation:
The question in English is basically find the area of the pink and blue area shown. The image is attached. This is Liza and Abby's blanket spread and we want the area of the whole shown.
<u>Solution:</u>
We want area of pink rectangle PLUS the blue region, which is a sum of lower rectangle and top triangle (if we cut it in this way).
First, area of pink rectangle:
Area = length * height
Area = 5 * 5.7
Area = 28.5
Now, the blue region, if broken down, lower portion is rectangle and upper portion is a triangle (we DISREGARD the overlapping region, of course!)
Lower Rectangle Area = length * height = 4 * 2 = 8
Upper triangle Area = 0.5 * base * height = 0.5 (4) * (6-2) = 0.5 * 4 * 4 = 8
So, blue region area = 8 + 8 = 16
<u>Total Area = 28.5 + 16 = 44.5 sq. ft.</u>
Answer:
V ≈ 263.9 units³
Step-by-step explanation:
The volume (V) of a cone is calculated as
V =
πr²h ( r is the radius and h the height )
Here r = 6 and h = 7 , then
V =
π × 6² × 7
=
π × 36 × 7
=
π × 252
= 84 π
≈ 263.9 units³ ( to 1 dec. place )
<span>The discriminant of a quadratic equation is the b^2-4ac portion that the square root is taken of. If the discriminant is negative, then the function has 2 imaginary roots, if the discriminant is equal to 0, then the function has only 1 real root, and finally, if the discriminant is greater than 0, the function has 2 real roots. So let's look at the equations and see which have a positive discriminant.
f(x) = x^2 + 6x + 8
6^2 - 4*1*8
36 - 32 = 4
Positive, so f(x) has 2 real roots.
g(x) = x^2 + 4x + 8
4^2 - 4*1*8
16 - 32 = -16
Negative, so g(x) does not have any real roots
h(x) = x^2 – 12x + 32
-12^2 - 4*1*32
144 - 128 = 16
Positive, so h(x) has 2 real roots.
k(x) = x^2 + 4x – 1
4^2 - 4*1*(-1)
16 - (-4) = 20
Positive, so k(x) has 2 real roots.
p(x) = 5x^2 + 5x + 4
5^2 - 4*5*4
25 - 80 = -55
Negative, so p(x) does not have any real roots
t(x) = x^2 – 2x – 15
-2^2 - 4*1*(-15)
4 - (-60) = 64
Positive, so t(x) has 2 real roots.</span>