Answer:
There are asymptotes at x = three-halves and x = negative one-third.
Step-by-step explanation:
f(x) = (x + 1)/ (6x^2 - 7x - 3)
= (x + 1)( / (6x^2 + 2x - 9x - 3)
= (x + 1) / (2x(3x + 1) - 3(3x + 1))
= (x + 1) / (2x - 3)(3x + 1)
Now x = 3/2 and x = -1/3 both make te denominator zero so these are both asymptotes.
We are asked in this problem to determine the simplified expression of the statement given. The rules that apply in exponential functions is that when an exponential term is raised to the power of an integer, the simplified term has a degree that is equal to the product of the integers involved. The operations involved should be applicable to terms with the same base number only. In this problem, we thus write:
2^3/4 / 2^1/2 = 2^3/4 * 2^-1/2 = = 2^(3/4 - 1/2) = 2^ 1/4. hence the answer is 2^0.25 or simply equal to 1.1892 determined using a calculator.
The answer would be D) x = 11.
Add 5 to both sides (5x = 50 + 5)
Simplify 50 + 5 to 55 (5x = 55)
Divide both sides by 5 (x = 55/5)
Simplify 55/5 to 11 (x = 11)
