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gladu [14]
3 years ago
14

Box 1 contains 1000 lightbulbs of which 10% are defective. box 2 contains 2000 lightbulbs of which 5% are defective. (a) suppose

a box is given to you at random and you randomly select a lightbulb from the box. if that lightbulb is defective, what is the probability you chose box 1? (b) suppose now that a box is given to you at random and you randomly select two light- bulbs from the box. if both lightbulbs are defective, what is the probability that you chose from box 1?
Mathematics
1 answer:
madreJ [45]3 years ago
6 0

hhhhhhhhhhhhhhhhhhhhhhhhh

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(Scientific Notation in the Real World MC)
Brrunno [24]

The average number of viewers over the two week is D. 4.85 x 10^5.

<h3>How to calculate the value?</h3>

It should be noted that the scientific notation simply has to do with writing of numbers that are either too large or too small. This will be illustrated thus:

In this case, the TV show had 5.6 x 10^5 viewers in the first week and 4.1 x 10^5 viewers in the second week.

Therefore, the average number of viewers over the two weeks will be:

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5 0
1 year ago
How to simplify [(-3)^2]^5?
Elenna [48]

First, solve the bracket:

(-3)^2 = (-3)(-3) = 9

Next, simplify

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hope this helps

8 0
3 years ago
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Consider testing Upper H 0 : mu equals 20H0: μ=20 against Upper H Subscript a Baseline : mu less than 20Ha: μ&lt;20 where muμ is
kolezko [41]

Answer:

Test: \mu < 20 with normal distⁿ

Hypothesis test:

H0:  \mu \ge 20                         (Null Hypothesis, H₀ : \mu = 20 is also correct)

H1: \mu < 20                             (Alternative Hypothesis, also called H₁)

This is lower tailed test.

Since sample is large, sample standard deviation can be taken as an  approximation of population standard deviation.

x = 19.3

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n = 444

significance level, \alpha = 0.05 (If no value is given, we take level of 0.05)

Test statistic z* = \frac{x-\mu}{\sigma/\sqrt{n}}

         

                         = \frac{19.3-20}{11.1/\sqrt{444}}

                       = - 1.33

The attached files contains additional information

6 0
3 years ago
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