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MrRa [10]

Answer:

About 99.7% of births would be expected to occur within 51 days of the mean pregnancy length

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Standard deviation = 17.

About what percentage of births would be expected to occur within 51 days of the mean pregnancy length?

51/17 = 3.

So, within 3 standard deviations of the mean.

About 99.7% of births would be expected to occur within 51 days of the mean pregnancy length

4 0

3 years ago

Suppose that prices of a certain model of a new home are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule t

levacccp [35]

Answer:

68% of buyers paid between $147,700 and $152,300.

Step-by-step explanation:

We are given that prices of a certain model of a new home are normally distributed with a mean of $150,000.

Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.

Let X = prices of a certain model of a new home

SO, X ~ Normal( $\mu=150,000 ,\sigma=2,300$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean price = $150,000

$\sigma$ = standard deviation = $2,300

Now, according to 68-95-99.7 rule;

Around 68% of the values in a normal distribution lies between $\mu-\sigma$ and $\mu-\sigma$ .

Around 95% of the values occur between $\mu-2\sigma$ and $\mu+2\sigma$ .

Around 99.7% of the values occur between $\mu-3\sigma$ and $\mu+3\sigma$ .

So, firstly we will find the z scores for both the values given;

Z = $\frac{X-\mu}{\sigma}$ = $\frac{147,700-150,000}{2,300}$ = -1

Z = $\frac{X-\mu}{\sigma}$ = $\frac{152,300-150,000}{2,300}$ = 1

This indicates that we are in the category of between $\mu-\sigma$ and $\mu-\sigma$ .

SO, this represents that percentage of buyers who paid between $147,700 and $152,300 is 68%.

7 0

3 years ago

Find the value of each variable. Round your answers to the nearest tenth. (Soh Coh Toa)

Butoxors [25]

Answer:

k = 8.4, j = 13.1

Step-by-step explanation:

Solve for k:

$tan(40)=\frac{k}{10}\\10(tan(40))=k\\8.4=k$

Solve for j:

$8.4^2+10^2=j^2\\70.56+100=j^2\\170.56=j^2\\13.1=j$

3 0

3 years ago

Read 2 more answers

Position Value of Term

Tasya [4]

The answer would be A, 2n+2. You could check this by plugging in your ordered pairs.

8 0

3 years ago

p: Two linear functions have different coefficients of x. q: The graphs of two functions intersect at exactly one point. Which s

miskamm [114]

The formula $q \Rightarrow p$ means that from statement q implies statement p.

When statements p="two linear functions have different coefficients of x" and q="the graphs of two functions intersect at exactly one point", then the statement $q \Rightarrow p$ have a form: "If the graphs of two functions intersect at exactly one point, then two linear functions have different coefficients of x."

7 0

3 years ago

Read 2 more answers